It should be noted that angle 2 and angle 1 are vertical angles and angle 2 and angle 5 are linear pair.
<h3>How to illustrate the information?</h3>
When two lines cross at a point, vertical angles are created. They are always on an equal footing. In other words, four angles are created anytime two lines cross or intersect. It is evident that two opposed angles are equal and are referred to as vertical angles.
When two lines cross at one point, a linear pair of angles is created. If the angles follow the intersection of the two lines in a straight line, they are said to be linear. A linear pair's total angles are always equal to 180°. These are also referred to as additional angles.
Therefore, it should be noted that angle 2 and angle 1 are vertical angles and angle 2 and angle 5 are linear pair.
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Answer:
y=4x-4
Step-by-step explanation:
Hi there!
we are given that a line has a slope of 4 and it contains the point (4, 12)
We want to write the equation of this line in slope-intercept form
Slope-intercept form is given as y=mx+b, where m is the slope and b is the y intercept
As we are already given the slope, we can immediately substitute it into the formula.
Replace m with 4 in y=mx+b:
y=4x+b
Now we need to find b
As the equation passes through the point (4, 12), we can use it to help solve for b
Substitute 4 as x and 12 as y:
12 = 4(4) + b
Multiply
12 = 16 + b
Subtract 16 from both sides
-4 = b
Substitute -4 as b
y = 4x - 4
Hope this helps!
Topic: Finding the equation of the line
See more on this topic here: brainly.com/question/27539102
X+y+5=0
y=-x-5
If a solution exists y=y so we can say
x^2-9x+10=-x-5 add x+5 to both sides
x^2-8x+15=0 now factor
x^2-3x-5x+15=0
x(x-3)-5(x-3)
(x-5)(x-3) so x=3 and 5, using y=-x-5
y(3)=-8 and y(5)=-10
So the two solutions are:
(3,-8) and (5,-10)
Answer:
0.91
Step-by-step explanation:
