Answer:
here ya go
Step-by-step explanation:
Log₄(2 – x) = log₄(–5x – 18).
Since the logs have the same basis (4) & are equal then:
(2 – x) = (–5x – 18). . Now solve for x & you will find x = -5
Find slope of line A:
Move into slope-intercept form y = mx+b
<span>5x + 8y = -9
8y = -5x - 9
y = (-5/8)x - 9/8
The slope of line A is -5/8.
If </span><span>Line B is perpendicular to line A, then
slope Line B = negative reciprocal of slope Line A</span>
<span>slope Line B = 8/5
So like B has the equation
y = (8/5)x + b
If it passes through (10,10), we know that when x = 10, y = 10. Use those values to solve for b:
</span>
<span>y = (8/5)x + b
10 = (8/5)·10 + b</span>
<span>10 = (8)·2 + b
10 = 16 + b
b = -6
So line B has equation </span>
<span>y = (8/5)x - 6
m = 8/5 and b = -6
so
m + b = 8/5 - 6 = 8/5 - 30/5 = -22/5
So m+b = -22/5 or -4.4 in decimal form
</span>
The answer to your question is C
Step-by-step explanation:
As
- The graph of the function passes through the point (2,1), and
- y increases by 4 when x increases by 1.
so
x y
2 1
3 5
4 9
5 13
6 17
and so on
From the table:
As the slope-intercept form of the line is
putting m=4 and any point, let say (2, 1) to find y-intercept 'b'.
So putting and in the slope-intercept form of the line
Therefore, the equation for the linear function will be:
