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3 years ago

How do I show work for -2x-7=3(4x+7)

Mathematics

2 answers:

Alona [7]3 years ago

5 0

Answer:

x=-2

Step-by-step explanation:

-2x-7=3(4x+7)

distribute

-2x-7 = 3*4x +3*7

-2x-7 = 12x+21

add 2x to each side

-2x-7+2x = 12x+2x+21

-7 = 14x+21

subtract 21 from each side

-7-21 = 14x+21-21

-28 = 14x

divide by 14

-28/14 = 14x/14

-2 =x

BARSIC [14]3 years ago

3 0

-2x - 7 = 3(4x + 7) Distribute/multiply 3 into (4x + 7)

-2x - 7 = 12x + 21 Add 2x on both sides

-2x + 2x - 7 = 12x + 2x + 21

-7 = 14x + 21 Subtract 21 on both sides

-7 - 21 = 14x + 21 - 21

-28 = 14x Divide 14 on both sides

-2 = x

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erma4kov [3.2K]

Answer: Choice A) 66 degrees

========================================================

Minor arc AB (marked in red in the attached diagram) is 45 degrees
Minor arc BE (marked in blue in the same diagram) is 87 degrees

Add the two arcs: 45+87 = 132

Then cut this value in half to get the inscribed angle ADE
132/2 = 66
We cut it in half due to the inscribed angle theorem

Notice how angle ADE cuts off arc ABE (which is composed of minor arc AB and and minor arc BE)

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3 years ago

Find n. 8/12 = n/48. n = ?

Novosadov [1.4K]

Answer:

n = 32

Step-by-step explanation:

Given:

$\frac{8}{12}=\frac{n}{48}$

Solve:

$\mathrm{Cross\; Multiply:}$

$\frac{8}{12}=\frac{n}{48}$

$\mathrm{48\times8=384}$

$\mathrm{384\div12=32}$

$\mathrm{Hence,n=32}$

~ $\mathrm{[Kavinsky]}$

7 0

3 years ago

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I really need someone to explain to me on how to solve these!! :(

HACTEHA [7]

Answer:

3.7%

Step-by-step explanation:

(p)principal=$3400

(t)time=9months=9÷12year=3÷4year

(i)interest=$94.50

(r)rate=?

we have

r%=i/(pt)

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r÷100=94.50÷2550

r=0.37×100

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3 years ago

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erastova [34]

12-13= yx this is that expression

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3 years ago

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Express the given integral as the limit of a riemann sum but do not evaluate: the integral from 0 to 3 of the quantity x cubed m

WARRIOR [948]

We will use the right Riemann sum. We can break this integral in two parts.
$\int_{0}^{3} (x^3-6x) dx=\int_{0}^{3} x^3 dx-6\int_{0}^{3} x dx$
We take the interval and we divide it n times:
$\Delta x=\frac{b-a}{n}=\frac{3}{n}$
The area of the i-th rectangle in the right Riemann sum is:
$A_i=\Delta xf(a+i\Delta x)=\Delta x f(i\Delta x)$
For the first part of our integral we have:
$A_i=\Delta x(i\Delta x)^3=(\Delta x)^4 i^3$
For the second part we have:
$A_i=-6\Delta x(i\Delta x)=-6(\Delta x)^2i$
We can now put it all together:
$\sum_{i=1}^{i=n} [(\Delta x)^4 i^3-6(\Delta x)^2i]\\\sum_{i=1}^{i=n}[ (\frac{3}{n})^4 i^3-6(\frac{3}{n})^2i]\\
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We can also write n-th partial sum:
$S_n=(\frac{3}{n})^4\cdot \frac{(n^2+n)^2}{4} -6(\frac{3}{n})^2\cdot \frac{n^2+n}{2}$

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4 years ago