Answer:
See explanation
Step-by-step explanation:
<h3 /><h3>Step 1</h3>
Miguel wins $2 is if he pulls two chips with the number 1.
<u>Probability of winning is:
</u>
- 2/4 * 1/3 = 1/6 as there are 4 chips in total
<u>
Probability of loosing is:</u>
<h3 /><h3>Step 2</h3>
<u>Missing values we found in the step 1, can be populated in the table:</u>
- Xi === 2 === -1
- P(Xi) === 1/6 === 5/6
<u>Expected Value as per table data:</u>
Expected value is $1/2 loss each time he plays
<h3 /><h3>Step 3</h3>
To make the game fair, the expected value should be zero.
<u>Then as per the calculation above, let's replace 2, with x, and find its value.</u>
- 1/6x + 5/6*(-1) = 0
- 1/6x = 5/6
- x= 5
So the amount should be $5 to make the game fair.
Answer:
The glass can hold 8. (I think)
Step-by-step explanation:
Answer:
The probability that event B will occur is 0.45
Step-by-step explanation:
Given;
probability that event A occurs, P(A) = 0.4
the probability that events A and B both occur, P(A ∩ B) = 0.25
the probability that either event A or event B occurs, P(A ∪ B) = 0.6
To determine the probability that event B will occur, we use probability addition rule;
P(A) + P(B) = P(A ∩ B) + P(A ∪ B)
0.4 + P(B) = 0.25 + 0.6
0.4 + P(B) = 0.85
P(B) = 0.85 - 0.4
P(B) = 0.45
Therefore, the probability that event B will occur is 0.45
Because your gonna elminate the loners and soon your going to substitute them for numbers
