Solve for yyy. a(n+y) = 10y+32a(n+y)=10y+32a

Mathematics

2 answers:

Phoenix [80]3 years ago

7 0

Answer:

y=32-an/a-10

Step-by-step explanation:

Khan academy says its correct so its the correct answer

Afina-wow [57]3 years ago

3 0

To solve for y, you need to separate it in one side and the other terms in the other side..... as follows:

<span>a(n+y)=10y+32a
an + ay = 10y + 32a

an - an + ay = 10y + 32a - an

ay = 10y + 32a - an

ay -10y = 32a - an

y (a-10) = (32 - n)a

y = {a(32-n)} / (a-10)

</span>

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