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svetoff [14.1K]
2 years ago
9

What am I supposed to do?

Mathematics
1 answer:
qaws [65]2 years ago
6 0

its a virus dont  fall for it

Step-by-step explanation:

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Suppose IQ scores were obtained from randomly selected couples. For 20 such pairs of​ people, the linear correlation coefficient
Brilliant_brown [7]

Answer:

108.88

Step-by-step explanation:

Given that:

Equation of Regression line obtained for couple's IQ:

y=9.88+0.9x

x represents the IQ score of the husband

The best predicted IQ of wife Given that husband's IQ is 110

y = 9.88 + 0.9(110)

y = 9.88 + 99

y = 108.88

6 0
2 years ago
What is the scientific notation of 6174798604
lesantik [10]
Here is your answer:

Since their no zeros (0) here's your answer:

6.174798604×10^9
7 0
2 years ago
Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)
EleoNora [17]
Start by multiplying each side of the inequality by \sqrt{x + 1} and simplifying:

2 \sqrt x + \frac{1}{\sqrt{x+1}}  \leq  2 \sqrt{x + 1}
(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})
2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)
2 \sqrt{x^2 + x} + 1 \leq 2x + 2
2 \sqrt{x^2 + x} \leq 2x + 1
\sqrt{x^2 + x} \leq x + \frac{1}{2}

From here, we can square both sides to get

x^2 + x \leq (x + \frac{1}{2})^2
x^2 + x \leq x^2 + x + \frac{1}{4}
0  \leq \frac{1}{4}, which is always true.
3 0
2 years ago
the diameter of a spherical basketball is 10 inches what is the volume of the basketball give the exact solution or round your a
DiKsa [7]
Volume of a sphere is 4/3(pi r ^3)

You were given d = 10 so r = 5

Then just plug and chug
7 0
3 years ago
Read 2 more answers
What is the answer here?
Angelina_Jolie [31]

Step-by-step explanation:

(4,-30) i am not 100% sure about it.

3 0
2 years ago
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