2 years ago

What am I supposed to do?

Mathematics

1 answer:

qaws [65]2 years ago

6 0

its a virus dont fall for it

Step-by-step explanation:

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Suppose IQ scores were obtained from randomly selected couples. For 20 such pairs of people, the linear correlation coefficient

Brilliant_brown [7]

Answer:

108.88

Step-by-step explanation:

Given that:

Equation of Regression line obtained for couple's IQ:

y=9.88+0.9x

x represents the IQ score of the husband

The best predicted IQ of wife Given that husband's IQ is 110

y = 9.88 + 0.9(110)

y = 9.88 + 99

y = 108.88

6 0

3 years ago

What is the scientific notation of 6174798604

lesantik [10]

Here is your answer:

Since their no zeros (0) here's your answer:

6.174798604×10^9

7 0

3 years ago

Prove 2√(x) + 1/√(x + 1) <= 2√(x+1) for all x in [0,inf)

EleoNora [17]

Start by multiplying each side of the inequality by $\sqrt{x + 1}$ and simplifying:

$2 \sqrt x + \frac{1}{\sqrt{x+1}} \leq 2 \sqrt{x + 1}$
$(2 \sqrt x + \frac{1}{\sqrt{x+1}})(\sqrt{x + 1}) \leq (2 \sqrt{x + 1})(\sqrt{x + 1})$
$2 \sqrt{x(x + 1)} + 1 \leq 2(x + 1)$
$2 \sqrt{x^2 + x} + 1 \leq 2x + 2$
$2 \sqrt{x^2 + x} \leq 2x + 1$
$\sqrt{x^2 + x} \leq x + \frac{1}{2}$

From here, we can square both sides to get

$x^2 + x \leq (x + \frac{1}{2})^2$
$x^2 + x \leq x^2 + x + \frac{1}{4}$
$0 \leq \frac{1}{4}$ , which is always true.

3 0

2 years ago

the diameter of a spherical basketball is 10 inches what is the volume of the basketball give the exact solution or round your a

DiKsa [7]

Volume of a sphere is 4/3(pi r ^3)

You were given d = 10 so r = 5

Then just plug and chug

7 0

3 years ago

Read 2 more answers

What is the answer here?

Angelina_Jolie [31]

Step-by-step explanation:

(4,-30) i am not 100% sure about it.

3 0

2 years ago