You would isolate the variable for ex
2x+3=9
2x=9-3
2x=6
x=3
First let’s divided 455 by 6.5 to figure out how far he travels in 1 hour which is equal to 70, now let’s do 2100 divided by 70, it will take 30 hours for him to drive 2100 miles.
Answer:
13,440
Step-by-step explanation:
10 possible digits 0 - 9
5 possible numbers for position 5 (odd digits only)
8 possible numbers for position 1 (cannot be zero or the odd number selected for position 5)
8 possible numbers remain for position 2 (10 minus 2 already selected)
7 possible numbers remain for position 3 (10 minus 3 already selected)
6 possible numbers remain for position 4 (10 minus 4 already selected)
5•8•8•7•6 = 13,440
Answer:
10 meters
Step-by-step explanation:
The given function
represents the height,
, in meters,
seconds after the ball is thrown.
Since the ball is thrown off the roof, then ball's height will be equal to the roof's height before being thrown (0 seconds). Therefore, substitute
into the given function
:

Therefore, the building is 10 meters tall.
To solve this we are going to use the compound interest formula

where:

is the investment

is the interest rate in decimal form

is the number of times the interest is compounded per year

is the time in years

is the amount after

years
First, lets convert the interest rate to decimal dividing it by 100%:

Next, lets find

. Since we know that the interest is compounded every 4 months (quarterly), it will be compounded

times in a year, so

.
We also know that

and

, so lets replace all the quantities into our compound interest formula:


Notice that the the number of years

is in the exponent, so we have to use logarithms to bring it down. But first lets divide both sides by 16000 to isolate the exponential expression:





Now that we know

, the last thing to do is convert 0.43 years to months:

We can conclude that Jimmy's investment will take
6 years and 5 months to reach $25,000.