This problem is a combination of the Poisson distribution and binomial distribution.
First, we need to find the probability of a single student sending less than 6 messages in a day, i.e.
P(X<6)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)
=0.006738+0.033690+0.084224+0.140374+0.175467+0.175467
= 0.615961
For ALL 20 students to send less than 6 messages, the probability is
P=C(20,20)*0.615961^20*(1-0.615961)^0
=6.18101*10^(-5) or approximately
=0.00006181
The answer to 150% of 22 is 33
Speed=15 m/s
1 hour=60 minutes
60 minutes=60 minutes (60 seconds/1 minute)=3600 seconds.
15 m/s=(15 m/s)(1 mile / 1609 m)(3600 s/1h)=33.56... miles/hour≈
≈33.6 miles/hour.
Answer: the speed in miles per hour would be 33.6 miles/hour
x intercept = where the function crosses the x axis (x,0)
y intercept = where the function crosses the y-axis (0,y)
A. y=7/2x-2
x intercept , replace y by 0 and solve for x:
0 =7/2x-2
2= 7/2 x
2 / (7/2) = x
x= 4/7
y-intercept, replace x by 0 and solve for y
y= 7/2x-2
y= 7/2 (0) -2
y=-2
B.
x-intercept:
x=-3
y-intercept
0=-3
It doesn't have a y-intercept.
It works out that: y = 1 or 5 and therefore x = 5 or 1
