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Stells [14]
3 years ago
10

I don't understand this. help please?

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0
The symbols used in question 3 are saying your x values can be anything, as long as x is larger than 0, so all the positive numbers
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3 years ago
Write the equation of a circle whose center is at (3,-2) and has a radius of 11.<br>Show your work!
Viefleur [7K]

Answer:

(x - 3)^{2} + (y + 2)^{2} = 121

Step-by-step explanation:

The equation of a circle has the following format:

(x - x_{0})^{2} + (y - y_{0})^{2} = r^{2}

In which r is the radius and the centre is the point (x_{0}, y_{0})

In this question:

Center at (3,-2), so x_{0} = 3, y_{0} = -2

Radius 11, so r = 11

Then

(x - 3)^{2} + (y - (-2))^{2} = 11^{2}

(x - 3)^{2} + (y + 2)^{2} = 121

3 0
2 years ago
Please I really need help my grade depends on it
DochEvi [55]

Answer:

24

Step-by-step explanation:

Given the solution

2 < x ≤ 24

The ≤ symbol means less than or equal to

Thus x can equal 24

At the other end 2 < x which means x cannot equal 2

Thus x = 24 will make the inequality true

5 0
3 years ago
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