Hi there!

The two trapezoids are similar, so we can determine a common scale factor:
OL/UR = NM/TS
9/3 = 6/2
3 = 3
Trapezoid ONML is 3x larger than UTSR, so:
RS = 4, LM = y
3RS = LM
3 · 4 = y = 12.
Find x using the same method:
3UT = ON
3(2x+1) = 4x + 9
6x + 3 = 4x + 9
2x = 6
x = 3.
Answer:
B
Step-by-step explanation:
Please mark as brainliest
18 and 35. The numbers whose sum 53 are 18 and 35.
The key to solve this problem is using a system of equations.
There are two numbers whose sum is 53. This number can be represented as x and y. So:
x + y = 53
Three times the smaller number is equal to 19 more than the larger. Let's set x as the smaller number and y the larger number. So:
3x = 19 + y
Clear y in both equations and let's use the equalization method to solve for x:
y = 53 - x and y = 3x - 19
Then,
53 - x = 3x - 19
53 + 19 = 3x + x ---------> 3x + x = 53 + 19 -------> 4x = 72
x = 72/4 = 18
To find y, let's substitute x = 18 in the equation x + y = 53
18 + y = 53 --------> y = 53 - 18
y = 35
Answer:
Unfortunately, we can't do anything with 41 as it has no factors. Since
is already simplified, try submitting that as your answer. If that doesn't work then try un-doing their steps and get rid of the 3:



Hope this helps!
to factor it the answer is (x+1)(x+1)
to simplify it the answer is x2+2x+1
idk if this helped or not but here you go