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4 years ago

Write the polynomial as a product: p^2q+r^2–pqr–pr Thanks so much! Love you all who help!

1 answer:

5 0

Factor the equation so...
(r^2-pr) and (p^2q-pqr)

Factor out (r^2-pr) = r(r-p)
Factor out (p^2q-pqr) = pq(p-r)

Add a negative to r(r-p) to make it -r(p-r)

(pq-r)(p-r) is the answer... I'm sorry I can't explain things well, but I tried.

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Amanda [17]

$\bf{Hello!}$

The answer is 140°

Because we can use exterior angle property here

Exterior angle property : It states that exterior angle is the sum of two opposite interior angles

y = 120 + 20 = 140°

6 0

3 years ago

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What is the slope of the line with points A and B?

marshall27 [118]

Answer:

-1

Step-by-step explanation:

A = (0,0)

B = (1,-1)

Slope = (-1-0)/(1-0) = -1/1 = -1

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3 years ago

Find the distance between ( -2, 5) (-2, 14).

WITCHER [35]

Answer:

Step-by-step explanation:

x didn't change in value, y changed by 9

the distance between the two points is 9

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3 years ago

Median for 35 45 26 32 46 38 39 40 26 72

zhenek [66]

Answer:

38.5

Step-by-step explanation:

4 0

3 years ago

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A bucket that weighs 4 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

jonny [76]

Answer:

2580 ft-lb

Step-by-step explanation:

Water leaks out of the bucket at a rate of $\frac{0.15 \mathrm{lb} / \mathrm{s}}{1.5 \mathrm{ft} / \mathrm{s}}=0.1 \mathrm{lb} / \mathrm{ft}$

Work done required to pull the bucket to the top of the well is given by integral

$W=\int_{a}^{b} F(x) dx$

Here, function $F(x)$ is the total weight of the bucket and water $x$ feet above the bottom of the well. That is,

$F(x)=4+(42-0.1 x)$

$=46-0.1x$

$a$ is the initial height and $b$ is the maximum height of well. That is,

$a=0 \text { and } b=60$

Find the work done as,

$W=\int_{a}^{b} F(x) d x$

$=\int_{0}^{60}(46-0.1 x) dx$

$&\left.=46x-0.05 x^{2}\right]_{0}^{60}$

$=(2760-180)-0[$

$=2580 \mathrm{ft}-\mathrm{lb}
$

Hence, the work done required to pull the bucket to the top of the well is $2580 \mathrm{ft}- \mathrm{lb}$

4 0

3 years ago