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4 years ago

[3(x+2)+2x]-[4(y+2)-3(y-2)]

Mathematics

2 answers:

Dafna11 [192]4 years ago

7 0

Answer:

5x-y-8

3(x+2)+2x-(4(y+2)-3(y-2))

4y+8-3(y-2)

3x+6+2x-y-14

and the last answer

skip some step hehehe

algol134 years ago

6 0

Hope this helps you out :D

Your answer is 5x-8-y

Step by step:
3(x+2)+2x-(4(y+2)-3(y-2))
Remove the parentheses
3x+6+2x-(4y+8-3y+6)
Calculate
3x+6+2x-(y+14)
Remove parentheses
3x+6+2x-y-14
Calculate
5x-8-y

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(58-x)-(x)=12 in one variable

tino4ka555 [31]

Answer:

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Step-by-step explanation:

Step 1: Write out equation

(58 - x) - (x) = 12

Step 2: Distribute negative

58 - x - x = 12

Step 3: Combine like terms

58 - 2x = 12

Step 4: Subtract 58 on both sides

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Step 5: Isolate x (divide both sides by -2)

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Answer:

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Step-by-step explanation:

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mezya [45]

Answer:

$8\sqrt2$

Second option is correct.

Step-by-step explanation:

We have been given the expression $(64)^{\frac{7}{12}}$

We can write the term 64 as $64=2^6$

Thus, we have

$(2^6)^{\frac{7}{12}}$

Now, use the exponent law $(x^m)^n=x^{mn}$

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On simplifying, we get

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This expression can be further simplified as

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Second option is correct.

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3 years ago

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den301095 [7]

Would it be 10-2?=8 quotient means divide

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