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STatiana [176]
3 years ago
10

Find the product and show your work 34,879 x 10 =

Mathematics
2 answers:
creativ13 [48]3 years ago
7 0

Answer:

34,879 × 10 = 348,790

Step-by-step explanation:

The answer is <em>348,790</em><em> </em>because 34,879 multipled by 10 is <em>348,790</em><em> </em>as shown in the picture above ^^

Assoli18 [71]3 years ago
5 0

Answer:

348790

Step-by-step explanation:

According to the Power of 10 rule, whenever you divide by 10 [⅒], you move the decimal mark to the left each time, and of course, whenever you multiply by 10, you move the decimal mark to the right each time. In this case, the decimal mark is just after the 2, so multiplying by 10 will add a zero to the number, making it 348790 [<em>three forty-eight thousand, eight hundred seventy-nine</em>].

I am joyous to assist you anytime.

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Write the polynomial f(x)=x^4-10x^3+25x^2-40x+84. In factored form
Verizon [17]
<h2>Steps:</h2>

So firstly, to factor this we need to first find the potential roots of this polynomial. To find it, the equation is \pm \frac{p}{q}, with p = the factors of the constant and q = the factors of the leading coefficient. In this case:

\textsf{leading coefficient = 1, constant = 84}\\\\p=1,2,3,4,6,7,12,14,21,28,42,84\\q=1\\\\\pm \frac{1,2,3,4,6,7,12,14,21,28,42,84}{1}\\\\\textsf{Potential roots =}\pm 1, \pm 2,\pm 3,\pm 4,\pm 6, \pm 7,\pm 12,\pm 14,\pm 21,\pm 28,\pm 42,\pm 84

Next, plug in the potential roots into x of the equation until one of them ends with a result of 0:

f(1)=(1)^4-10(1)^3+25(1)^2-40(1)+84\\f(1)=1-10+25-40+84\\f(1)=60\ \textsf{Not a root}\\\\f(2)=2^4-10(2)^3+25(2)^2-40(2)+84\\f(2)=16-10*8+25*4-80+84\\f(2)=16-80+100-80+84\\f(2)=80\ \textsf{Not a root}\\\\f(3)=3^4-10(3)^3+25(3)^2-40(3)+84\\f(3)=81-10*27+25*9-120+84\\f(3)=81-270+225-120+84\\f(3)=0\ \textsf{Is a root}

Since we know that 3 is a root, this means that one of the factors is (x - 3). Now that we know one of the roots, we are going to use synthetic division to divide the polynomial. To set it up, place the root of the divisor, in this case 3 from x - 3, on the left side and the coefficients of the original polynomial on the right side as such:

  • 3 | 1 - 10 + 25 - 40 + 84
  • _________________

Firstly, drop the 1:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓
  • _________________
  •     1

Next, multiply 3 and 1, then add the product with -10:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓ + 3
  • _________________
  •     1  - 7

Next, multiply 3 and -7, then add the product with 25:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓ + 3  - 21
  • _________________
  •     1  - 7 + 4

Next, multiply 3 and 4, then add the product with -40:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓ + 3  - 21 + 12
  • _________________
  •     1  - 7  +  4  - 28

Lastly, multiply -28 and 3, then add the product with 84:

  • 3 | 1 - 10 + 25 - 40 + 84
  •     ↓ + 3  - 21 + 12  - 84
  • _________________
  •     1  - 7  +  4  - 28 + 0

Now our synthetic division is complete. Now since the degree of the original polynomial is 4, this means our quotient has a degree of 3 and follows the format ax^3+bx^2+cx+d . In this case, our quotient is x^3-7x^2+4x-28 .

So right now, our equation looks like this:

f(x)=(x-3)(x^3-7x^2+4x-28)

However, our second factor can be further simplified. For the second factor, I will be factoring by grouping. So factor x³ - 7x² and 4x - 28 separately. Make sure that they have the same quantity inside the parentheses:

f(x)=(x-3)(x^2(x-7)+4(x-7))

Now it can be rewritten as:

f(x)=(x-3)(x^2+4)(x-7)

<h2>Answer:</h2>

Since the polynomial cannot be further simplified, your answer is:

f(x)=(x-3)(x^2+4)(x-7)

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Answer:

r= d/2

7/2

3.5

3.5 is the answer

Step-by-step explanation:

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Which ordered pair represents a point on a line y = 2x +1. a. 0,3 b. 1,2 c. 2,1 d. -1,-1.
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The solution to a system of equations is (6-3). Choose two equations that might make up the system. Y= -3x+6 Y=2x-9 y=-5x+27 y=2
MakcuM [25]

Answer:  C) y = -5x + 27     and       D) y = 2x - 15

<u>Step-by-step explanation:</u>

Substitute x = 6 and y = -3 into each of the given equations to see which result in a TRUE statement.

A) y = -3x + 6

  -3 = -3(6) + 6

  -3 = -18 + 6

  -3 = -12     FALSE

B) y = 2x - 9

  -3 = 2(6) - 9

   -3 = 12 - 9

   -3 = 3     FALSE

C) y = -5x + 27

  -3 = -5(6) + 27

  -3 = -30 + 27

  -3 = -3    TRUE!

D) y = 2x - 15

  -3 = 2(6) - 15

  -3 = 12 - 15

  -3 = -3    TRUE!

E) y = -4x + 27

  -3 = -4(6) + 27

  -3 = -24 + 27

  -3 = 3   FALSE

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3 years ago
Domain and range of y = x2 + 9
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Algebra Examples

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined. The range is the set of all valid y values.

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2 years ago
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