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Paladinen [302]
2 years ago
5

Can someone help me.​

Mathematics
2 answers:
salantis [7]2 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

substitute the values of x in the table into g(x)

Using the rule of exponents

a^{-m} = \frac{1}{a^{m} }

g(- 2) = 4^{-2} = \frac{1}{4^{2} } = \frac{1}{16}

g(- 1) = 4^{-1} = \frac{1}{4}

g(0) = 4^{0} = 1

g(1) = 4^{1} = 4

g(2) = 4² = 16

xxMikexx [17]2 years ago
5 0
Someone already answered it but use Symbolab to help you with math problems
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the width of a rectangle is 12 cm less than the length the perimeter is 156 cm. Find the with and length
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We know that the perimeter of a rectangle is twice the length, plus twice the width.  

P = 2L + 2W  

We also know that the perimeter is 156.  

P = 156  

Finally, we know that the width is 12 less than the length.  

W = L - 12.  

The next thing that we do is substitute the information that we have into the original equation:  

P = 2L + 2W  

156 = 2L + 2(L - 12)  

From this point we start to solve  

156 = 2L + 2L - 24 <---we multiplied the '2' through the parenthesis  

156 + 24 = 2L + 2L - 24 + 24  

180 = 2L + 2L <--- getting like terms on same sides  

180 = 4L <---combining like terms  

180/4 = 4L/4 <--- getting like terms on same sides  

45 = L <---now we have a value for L  

Now we take the known value for L and substitute it in to our equation for W  

W = L - 12  

W = 45 - 12  

W = 33  

So now we have Length = 45 and Width = 33.

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2 years ago
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