158, because to solve this question we first need to know the formula for finding the surface area of a rectangular prism which is A=<span>2<span>(<span><span><span>wl</span>+<span>hl</span></span>+<span>hw</span></span><span>) then you just need to input the numbers like so A=2(5*3+8*3+8*5) then when you simplify this down you get A=2(79) then distribute like so so A=158
Enjoy!=)</span></span></span>
please edit your question man
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
The question presented is not answerable because it just presented a mere statement.