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3 years ago

Help please this math is hard just number 3 the one that has no writing

Mathematics

1 answer:

Colt1911 [192]3 years ago

6 0

You actually have most of the answers correct.
E is the origin
D is the x axis
A is the y axis
B is at coordinates (1, 3)
C is at coordinates (3, 1)
*remember you go across on the graph x axis and then up y axis.

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You cannot remember your 4-digit bike-lock combination. What is the probability that you guess the combination correctly? (Enter

Svetradugi [14.3K]

1/10000 every try

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3 0

3 years ago

QUESTION 2. the feasible region shows the number of chairs x and tables y that a furniture company can build each week.

GalinKa [24]

Answer:

Part a) The company can not build 12 chairs and 5 tables

Part b) The company can build 18 chairs and 3 tables

Part c) The company can build 12,13,14,15,16 or 17 chairs

Step-by-step explanation:

we know that

If a ordered pair is a solution, then the ordered pair must be belong to the feasible region of the graph

Part a) Can the company build 12 chairs and 5 tables?

In this problem we have the ordered pair A(12,5)

Plot and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point A is not on the feasible region

therefore

The company can not build 12 chairs and 5 tables

Part b) Can the company build 18 chairs and 3 tables?

In this problem we have the ordered pair B(18,3)

Plot and verify if the point belong to the feasible region of the graph

see the attached figure to better understand the problem

The point B is on the feasible region

therefore

The company can build 18 chairs and 3 tables

Part c) One week, the company decides to build 4 tables. how many chairs can the company build?

For y=4

Find the value of x in the graph

The solutions point for y=4 tables are

(12,4), (13,4),(14,4),(15,4),(16,4) and (17,4)

therefore

The company can build 12,13,14,15,16 or 17 chairs

3 0

3 years ago

Suppose that administrators at a large urban high school want to gain a better understanding of the prevalence of bullying withi

boyakko [2]

Answer:

lower limit =0.261

upper limit =0.369

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Description in words of the parameter p

$p$ represent the real population proportion of people that have experienced bullying

X= 63 people in the random sample that have experienced bullying

n=200 is the sample size required

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that have experienced bullying

$z_{\alpha/2}$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Numerical estimate for p

In order to estimate a proportion we use this formula:

$\hat p =\frac{X}{n}$ where X represent the number of people with a characteristic and n the total sample size selected.

$\hat p=\frac{63}{200}=0.315$ represent the estimated proportion of people that they were planning to pursue a graduate degree

Confidence interval

The confidence interval for a proportion is given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.90=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.261$

$0.315 - 1.64 \sqrt{\frac{0.315(1-0.315)}{200}}=0.369$

And the 90% confidence interval would be given (0.261;0.369).

We are confident at 90% that the true proportion of people that they were planning to pursue a graduate degree is between (0.261;0.369).

lower limit =0.261

upper limit =0.369

5 0

3 years ago

PLEASE HELP ME WITH THIS QUESTION!!!!!

prohojiy [21]

Answer:

we have, 1953125=5⁹, so it cannot be a perfect square. If the last digit of a given number is 5, then the last three digits must be perfect squares, 025 or 225 or 625. Otherwise, that number cannot be a perfect square. And as 125 is not a perfect square, so no number ending with 125 can be a perfect square

4 0

2 years ago

Read 2 more answers

The circumference is 15pi centimeters. what is the area of the circle in terms of pi.

Alborosie

Answer:

$\pi {r}^{2}$

6 0

3 years ago