In which career would you most likely apply concepts from geometry?

What is an equation of the line that passes through the points (5, 2) and (−5,−6)?

kirza4 [7]

Don’t really know but you have to trust me that if it’s multiple-choice it’s a or B trust me OK it helps

6 0

2 years ago

An online furniture store sells chairs and tables. Each day, the store can ship at most 25 pieces of furniture. Write an inequal

yanalaym [24]

9514 1404 393

Answer:

t + c ≤ 25

Step-by-step explanation:

"At most 25" means "less than or equal to 25." The total number of pieces of furniture is the sum of the numbers of tables and of chairs: t + c.

The shipping constraint can be written as ...

t + c ≤ 25

4 0

3 years ago

Solve for x. Show your work.<br> 1 x<-12<br> 2

Airida [17]

Answer:

2 is not a solution

Step-by-step explanation:

x < -12

<u>Step 1: Check if 2 is less than -12</u>

2 < -12

No, this doesn't work

Answer: 2 is not a solution

5 0

4 years ago

The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0

3 years ago

An elevator moves at a constant speed of 20 feet per second. Arturo correctly graphs this proportional relationship on a coordin

lyudmila [28]

Well he would start from 0y and point 20e to make a sifishint graph

3 0

3 years ago