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3 years ago

Who's friendships have changed since middle school? How?

Mathematics

1 answer:

makkiz [27]3 years ago

4 0

Answer:

Mine

Step-by-step explanation:

Mine because people change up and everybody is not your friend everyone always have alot of animosity towards me but I didn't care anyways because my motha raised me to not have friends thats why i'm antisocial

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-80,20,-5,1.25 find the common ratio

Ostrovityanka [42]

Answer:

you divide by -4 every time

4 0

2 years ago

PLEASE HELP FASTT!!!! FOR BRAINLIEST!

vfiekz [6]

Your answer is L = 11 cm.

If the volumes of both shapes are the same, then we can set them equal to each other and solve for L to find the answer.

The volume of a rectangular prism is base × height × depth, which comes to 5 × 6 × L = 30L

The volume of the trapezoid prism (the shape on the left) would be the area of the trapezoid on the front, multiplied by the depth. This gives you:

$\frac{7 + 4}{2}$ × 6 × 10 = 5.5 × 6 × 10 = 330

So now we get:

330 = 30L

÷ 30

L = 11

I hope this helps!

6 0

4 years ago

Read 2 more answers

A video game awards 25 points for defeating a monster and 85 additional points for getting to the end of a stage.

Vilka [71]

Answer:

p=25m+85

Step-by-step explanation:

..............................

7 0

3 years ago

Enter the decimal equivalent of 53/100

Paha777 [63]

Decimal : 0.53
percentage : 53%

8 0

3 years ago

The spread of a virus is modeled by V (t) = −t 3 + t 2 + 12t,

VashaNatasha [74]

Functions can be used to model real life scenarios

The reasonable domain is $\mathbf{[0,\infty)}$ .
The average rate of change from t = 0 to 2 is 20 persons per week
The instantaneous rate of change is $\mathbf{V'(t) = -3t^2 + 2t + 12}$ .
The slope of the tangent line at point (2,V(20) is 10
The rate of infection at the maximum point is 8.79 people per week

The function is given as:

$\mathbf{V(t) = -t^3 + t^2 + 12t}$

(a) Sketch V(t)

See attachment for the graph of $\mathbf{V(t) = -t^3 + t^2 + 12t}$

(b) The reasonable domain

t represents the number of weeks.

This means that: t cannot be negative.

So, the reasonable domain is: $\mathbf{[0,\infty)}$

(c) Average rate of change from t = 0 to 2

This is calculated as:

$\mathbf{m = \frac{V(a) - V(b)}{a - b}}$

So, we have:

$\mathbf{m = \frac{V(2) - V(0)}{2 - 0}}$

$\mathbf{m = \frac{V(2) - V(0)}{2}}$

Calculate V(2) and V(0)

$\mathbf{V(2) = (-2)^3 + (2)^2 + 12 \times 2 = 20}$

$\mathbf{V(0) = (0)^3 + (0)^2 + 12 \times 0 = 0}$

So, we have:

$\mathbf{m = \frac{20 - 0}{2}}$

$\mathbf{m = \frac{20}{2}}$

$\mathbf{m = 10}$

Hence, the average rate of change from t = 0 to 2 is 20

(d) The instantaneous rate of change using limits

$\mathbf{V(t) = -t^3 + t^2 + 12t}$

The instantaneous rate of change is calculated as:

$\mathbf{V'(t) = \lim_{h \to \infty} \frac{V(t + h) - V(t)}{h}}$

So, we have:

$\mathbf{V(t + h) = (-(t + h))^3 + (t + h)^2 + 12(t + h)}$

$\mathbf{V(t + h) = (-t - h)^3 + (t + h)^2 + 12(t + h)}$

Expand

$\mathbf{V(t + h) = (-t)^3 +3(-t)^2(-h) +3(-t)(-h)^2 + (-h)^3 + t^2 + 2th+ h^2 + 12t + 12h}$ $\mathbf{V(t + h) = -t^3 -3t^2h -3th^2 - h^3 + t^2 + 2th+ h^2 + 12t + 12h}$