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Nady [450]
3 years ago
7

Equation:

Mathematics
1 answer:
puteri [66]3 years ago
7 0

Answer:

the answer is 988 .........

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Find dy/dx............
PolarNik [594]

Answer:

dy/dx = (1 / x^3 + x) × (3x² + 1) × (1/2)

Step-by-step explanation:

y = log[ x² × √(x² + 1) ]

y = log[ √(x(x² + 1)) ]

y = log[ √(x^3 + x) ]

y = log[ √(x^3 + x) ]

Now, let a = √(x^3 + x)

Then y = log(a)

Find dy/da.

y = log(a)

dy/da = (1 / a)

dy/da = (1 / √(x^3 + x))

Find da/dx using chain rule.

a = √(x^3 + x)

Let b = x^3 + x, then a = √b

da/dx = (db / dx) × (da / db)

da/dx = (3x² + 1) × (1/2)× (b)^(-1/2)

da/dx = (3x² + 1) × (1/2)× (x^3 + x)^(-1/2)

Finally, find dy/dx using chain rule.

dy/dx = (dy/da) × (da/dx)

dy/dx = (1 / √(x^3 + x)) × (3x² + 1) × (1/2)×

(x^3 + x)^(-1/2)

dy/dx = (1 / (x^3 + x)) × (3x² + 1) × (1/2)

5 0
3 years ago
3n=30+3n(n-4) Find n. .-.​
Yuri [45]

Answer:

n=6

Step-by-step explanation:

6n= 30+3(n-4)

6n=30+3n-12

6n-3n=30-12

3n=18

n=18/3

n=6

8 0
3 years ago
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Can someone help with this please??
finlep [7]
4, 5 & 6 were answered on another question plus the circle isn't shown on this one.

7. semi circle is half a circle, there re 4 arcs smaller then half
 they are DB, DC, AC and AB

last choice is correct

4 0
3 years ago
Help me plzzzzz zzzzzz
Anvisha [2.4K]

Answer:

B.

Step-by-step explanation:

8 0
3 years ago
Which set of angle measures CANNOT be the angle measures of a triangle? *
Lera25 [3.4K]

Answer:

A

Step-by-step explanation:

All triangles have 180 degrees, these set of measures do not add up to 180°. They add up to 181°, so it is the answer.

6 0
3 years ago
Read 2 more answers
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