This depends as to whether you are just multiplying the square root by 3, or are doing a cube root function. In a cube root, the 3 would be located just at the bent part of the square root symbol, usually in a smaller font. If one just wanted to multiply a square root by 3, it does not matter whether or not the 3 comes before or after the root.
A cube root is equal to a value to the power of (1/3).
I hope this helps
Answer:
Step-by-step explanation:
Given data:
SS={0,1,2,3,4}
Let probability of moving to the right be = P
Then probability of moving to the left is =1-P
The transition probability matrix is:
![\left[\begin{array}{ccccc}1&P&0&0&0\\1-P&1&P&0&0\\0&1-P&1&P&0\\0&0&1-P&1&P\\0&0&0&1-P&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D1%26P%260%260%260%5C%5C1-P%261%26P%260%260%5C%5C0%261-P%261%26P%260%5C%5C0%260%261-P%261%26P%5C%5C0%260%260%261-P%261%5Cend%7Barray%7D%5Cright%5D)
Calculating the limiting probabilities:
π0=π0+Pπ1 eq(1)
π1=(1-P)π0+π1+Pπ2 eq(2)
π2=(1-P)π1+π2+Pπ3 eq(3)
π3=(1-P)π2+π3+Pπ4 eq(4)
π4=(1-P)π3+π4 eq(5)
π0+π1+π2+π3+π4=1
π0-π0-Pπ1=0
→π1 = 0
substituting value of π1 in eq(2)
(1-P)π0+Pπ2=0
from
π2=(1-P)π1+π2+Pπ3
we get
(1-P)π1+Pπ3 = 0
from
π3=(1-P)π2+π3+Pπ4
we get
(1-P)π2+Pπ4 =0
from π4=(1-P)π3+π4
→π3=0
substituting values of π1 and π3 in eq(3)
→π2=0
Now
π0+π1+π2+π3+π4=0
π0+π4=1
π0=0.5
π4=0.5
So limiting probabilities are {0.5,0,0,0,0.5}
Answer:
1. 8.576%
2. Yes
Step-by-step explanation:
1. Use the calculator
Enter: normalcdf(8, E99, 0, 5.9)
This is equal to .08756.
Convert this number into a percent = 8.756%
2.
First, calculate the residual
Residual = Observed - Predicted = 165 - 2.599(20) + 105.08 = 7.94
Use the calculator
Enter: normalcdf(7.94, E99, 0, 5.9)
This is equal to .0892.
Convert this number into a percent = 8.92%
This would be surprising, because the chance of this happening is very low.
Answer:
The answers is 8.06on DeltaMath
Step-by-step explanation:
