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3 years ago

HELP IN NUMBER 3 plz !!!

Mathematics

1 answer:

DanielleElmas [232]3 years ago

5 0

8.1• 10^10. U need to move the decimal to the right 10 places. Then compare from the other things from the problem.

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When I add two to my number and then multiply it by five, I get thirty. What is my number?

rjkz [21]

30/5= 6
6 - 2 = 4
Your number is four

6 0

2 years ago

Read 2 more answers

3(3b +2)=-30 what is b =

ycow [4]

3(3b+2)=-30 perform indicated multiplication on left side...

9b+6=-30 subtract 6 from both sides

9b=-36 divide both sides by 9

b=-4

4 0

2 years ago

Please HELP! I DON'T KNOW HOW CAN I SOLVE THIS

Wewaii [24]

Answer:

Step-by-step explanation:

The Pythagorean Theorem:

$leg^2+leg^2=hypotenuse^2\to a^2+b^2=c^2$

$41.\\\\a=1,\ b=1,\ c=x\\\\x^2=1^2+1^2\\\\x^2=1+1\\\\x^2=2\to x=\sqrt2$

$42.\\a=1, b=2,\ c=x\\\\x^2=1^2+2^2\\\\x^2=1+4\\\\x^2=5\to x=\sqrt5$

$43.\\a=3,\ b=x,\ c=5\\\\3^2+x^2=5^2\\\\9+x^2=25\qquad\text{subtract 9 from both sides}\\\\x^2=16\to x=\sqrt{16}\to x=4$

$44.\\\\a=4,\ b=x,\ c=8\\\\4^2+x^2=8^2\\\\16+x^2=64\qquad\text{subtract 16 from both sides}\\\\x^2=48\to x=\sqrt{48}\\\\x=\sqrt{16\cdot3}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\x=\sqrt{16}\cdot\sqrt3\\\\x=4\sqrt3$

7 0

2 years ago

Read 2 more answers

Please help <br> Algebra 1<br> Look at the photo below...

I am Lyosha [343]

horizontal line: x=9

vertical line: y=3

You can plug it into the application demos to see it visually just put y=3 on one line and x=9 on the other

7 0

3 years ago

How to prove this using trig identities?

Pavlova-9 [17]

Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

= (sin2B + cos2B)/[(cosB)(sinB)]

= 1/[(cosB)(sinB)]

= (1/cosB)(1/sinB)

= (secB)(cscB)

7 0

2 years ago