Answer:
1 and -2
Step-by-step explanation:
-2x^2=2x-4 so 2x^2 + 2x -4 = 0
2(x^2+x-2)=0
x^2+x-2 = (x-1)(x+2)
x=1 x=-2
The solution set of the equation 3X=-6/1-X for x # 1 is {-2,1)
3x = -6/(1-x)
3x(1-x) = -6
3x – 3x2 = -6
Taking 3 as common from both sides
x –x2 = -2
x2 – x +2 =0
Using factorisation method we will get two factors
Factoring quadratics is a method of expressing the quadratic equation ax2 + bx + c = 0 as a product of its linear factors as (x - k)(x - h), where h, k are the roots of the quadratic equation ax2 + bx + c = 0. This method is also is called the method of factorization of quadratic equations. Factorization of quadratic equations can be done using different methods such as splitting the middle term, using the quadratic formula, completing the squares, etc.
( x – 2)(x+1)=0
So, x = 2 , -1
Now, when x ≠ 1
The solution of the equation will vary from {-2,1) .
Learn more about the factorisation here brainly.com/question/13496719
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A could be 2 while B could be 3, so -2a+3b turns into -4+9, which equals 5.
From what I know you can't really solve a a single equation with two-variables so it's just a matter of trial and error.
Just try plugging in a small number like 2 for a just to try it and you get 8b^2=72.
Divide everything by 8 to isolate b and you get that b^2=9.
Square root everything and you'll find that b=3. This is just one possible combination, I'm sure there are many more but this is obviously the one that was intended to be found.
Now that we know that a=2 and b=3 just plug them into the equation.
-2(2)+3(3)=?
-4+9=?
5
Sorry about having to use this ^ symbol, the equation maker is not working.
