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valentina_108 [34]
4 years ago
15

Classify the following lines as either parallel, intersecting, coincident, or skew. In each case find the measure of the acute a

ngle between them?
Mathematics
1 answer:
solong [7]4 years ago
8 0

Answer:

The lines are parallel with an acute angle of 0 degrees.

Missing Information:

The equations of lines are missing which are as follows:

<u>Line 1:</u>

x = 1 - 2t , y = 8 + t, z = 5

<u>Line 2:</u>

x = 2 + 4s , y = -1 -2s, z = 3

Step-by-step explanation:

First, we need to find the direction vectors of both the line, we can write them as:

Direction Vector of line 1 =D_{1}= -2u + 1v + 0w

Direction Vector of line 2= D_{2}=4u -2v+0w

As we can see,

D_{2}=-2 D_{1}

such that:

4u -2v+0w= -2(-2u + 1v + 0w)

Since,

D_{2}=-2 D_{1}

So the lines are parallel such that<u> θ= 0 degrees.</u> (Which is the acute angle between them)

All the points on line 1 have z-coordinate as 5 (z=5),

All the points on line 2 have z-coordinate as 3 (z=3),

Since the z-coordinate do not match , so the lines are not coincident.

Also as the lines are parallel so they are not intersecting.

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Answer:

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Step-by-step explanation:

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The general equation of a circle has the following form

(x-h)^2 + (y-k)^2 = r^2

Where r is the radius and the point (h, k) is the center of the circle

To transform the given equation in the general equation of a circumference we must use the method of square completions

Step 1

(x^2 - 4x) + (y^2 + 8y) = -4

<u>Step 2</u>

<u> </u>Add and subtract (\frac{b}{2})^2 For an equation of the form

ax^2 +bx +c

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<u>Step 4 Simplify</u>

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Finally

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The center is:

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