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2 years ago

5

Solve Px+17=12 for x

1 answer:

Hoochie [10]2 years ago

4 0

Answer:
x = -5/P

Explanation:
We are given
Px + 17 = 12

Subtract 17 on both sides using the Subtraction Property of Equality
Px = -5

Divide both sides by P to isolate *x* by itself using the Division Property of Equality
x = -5/P

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Evaluate if x = 1 , y = 3 , and z = 5<br><br> |5z - 2y|

Aleks04 [339]

Answer:

1

Step-by-step explanation:

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3 years ago

How do we put the points (0,7) and (8,-2) into slope intercept form

Vinil7 [7]

The formula for slope intercept form is y=mx+b where x is the slope and b is the y intercept. To find the slope you would have to do -2-7 over 8-0 and that would give you -9/8. That would be your slope. And I think you should be given a graph I’m not sure but if there is look at it and see what point you see on the y axis

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3 years ago

Surface area helpp needed

Firlakuza [10]

Answer:

144 un²

Step-by-step explanation:

Front Parallelogram = 5 x 11 = 55

Two triangles = 3 x 4 = 12

Back Parallelogram = 3 x 11 = 33

Bottom rectangle = 4 x 11 = 44

Total =

55 + 12 + 33 + 44 = 144

units = un²

144 un²

If my answer is incorrect, pls correct me!

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5 0

3 years ago

Drag the tiles to the boxes to form correct pairs.<br> Match the pairs of equivalent expressions.

Rashid [163]

Answer:

The following pairs/results are matched:

$5\left(2t+1\right)+\left(-7t+28\right)$ = $3t+33$
$3\left(3t-4\right)-\left(2t+10\right)$ = $7t-22$

$\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)$ = $\frac{16t}{3}-\frac{23}{5}$

$\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)$ = $-\frac{11}{4}t+36$

Step-by-step explanation:

Lets solve all the expressions to match the results.

$5\left(2t+1\right)+\left(-7t+28\right)$

<em>Solving the expression</em>

$5\left(2t+1\right)+\left(-7t+28\right)$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$5\left(2t+1\right)-7t+28$

$10t+5-7t+28$

$3t+33$

Therefore, $5\left(2t+1\right)+\left(-7t+28\right)$ = $3t+33$

$3\left(3t-4\right)-\left(2t+10\right)$

<em>Solving the expression</em>

$3\left(3t-4\right)-\left(2t+10\right)$

$9t-12-\left(2t+10\right)$

$9t-12-2t-10$

$7t-22$

Therefore, $3\left(3t-4\right)-\left(2t+10\right)$ = $7t-22$

$\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)$

<em>Solving the expression</em>

$\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$4t-\frac{8}{5}-\left(3-\frac{4}{3}t\right)$

$4t-\frac{8}{5}-\left(-\frac{4t}{3}+3\right)$

$4t-\frac{8}{5}-3+\frac{4t}{3}$

As

$-3-\frac{8}{5}:\quad -\frac{23}{5}$ and $\frac{4t}{3}+4t:\quad \frac{16t}{3}$

So,

$4t-\frac{8}{5}-3+\frac{4t}{3}$ will become $\frac{16t}{3}-\frac{23}{5}$

Therefore, $\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)$ = $\frac{16t}{3}-\frac{23}{5}$

$\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)$

<em>Solving the expression</em>

$\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$-\frac{9}{2}t+3+\frac{7}{4}t+33$

$\mathrm{Group\:like\:terms}$

$\frac{9}{2}t+\frac{7}{4}t+3+33$

$\mathrm{Add\:similar\:elements:}\:-\frac{9}{2}t+\frac{7}{4}t=-\frac{11}{4}t$

$-\frac{11}{4}t+3+33$

$-\frac{11}{4}t+36$

Therefore, $\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)$ = $-\frac{11}{4}t+36$

Thus, the following pairs/results are matched:

$5\left(2t+1\right)+\left(-7t+28\right)$ = $3t+33$
$3\left(3t-4\right)-\left(2t+10\right)$ = $7t-22$

$\left(4t-\frac{8}{5}\right)-\left(3-\frac{4}{3}t\right)$ = $\frac{16t}{3}-\frac{23}{5}$

$\left(-\frac{9}{2}t+3\right)+\left(\frac{7}{4}t+33\right)$ = $-\frac{11}{4}t+36$

Keywords: algebraic expression

Learn more about algebraic expression from brainly.com/question/11336599

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5 0

3 years ago

Read 2 more answers

Write the first three terms in the following sequences. Identify them as arithmetic or geometric

vaieri [72.5K]

Answer:

$A(1)=9$

$A(2)=4$

$A(3)=-1$

Arithmetic sequence

Step-by-step explanation:

We are given that

$A(n+1)=A(n)-5 \;for\;n\geq 1$ A(1)=9

We have to find first three terms and identify the sequence is geometric or arithmetic.

Substitute n=1

Then, we get

$A(2)=A(1)-5=9-5=4$

For n=2

$A(3)=A(2)-5=4-5=-1$

For n=3

$A(4)=-1-5=-6$

$d_1=A_2-A_1=4-9=-5$

$d_2=A_3-A_2=-1-4=-5$

$d_3=A_4-A_3=-6+1=-5$

$d_1=d_2=d_3=-5$

When the difference of consecutive terms are constant then the sequence is arithmetic sequence.

Therefore, given sequence is arithmetic sequence.

8 0

3 years ago