Answer:
a) 0.32
b) 0.68
c) office or den
Step-by-step explanation:
Locations Probabilities
Adult bedroom 0.03
Child bedroom 0.15
Other bedroom 0.14
Office or den 0.40
Other rooms 0.28
a)
P(PC in bedroom)= P(PC in adult bedroom)+ P(PC in child bedroom)+ P(PC in other bedroom)
P(PC in bedroom)= 0.03+0.15+ 0.14
P(PC in bedroom)= 0.32.
Thus, the probability that a PC is in a bedroom is 0.32.
b)
P(PC is not in bedroom)= P(PC in Office or den)+ P(PC in Other rooms)
P(PC is not in bedroom)= 0.40+0.28
P(PC is not in bedroom)= 0.68.
Thus, the probability that a PC is not in a bedroom is 0.68.
c)
When a household is selected at random from households with a PC we would expect to find a PC in a room which has a greater probability of having PC.
The greater probability of room having a PC is of Office or den room with probability 0.40. So, when a household is selected at random from households with a PC we would expect to find a PC in a Office or den room.
Minimum is (4,3) and Vertical intercept is (0,5) correct me if I’m wrong
Answer:
A: 2 boxes
B:3 more boxes
Step-by-step explanation:
Attached a picture. Hope this helps!