All categories

2 years ago

Find the area of the triangle

Mathematics

2 answers:

Romashka [77]2 years ago

8 0

Area of a triangle is 1/2 x base x height

Base is given as 19 ft and height is given as 14 ft

Area = 1/2 x 19 x 14 = 133 square ft

Serggg [28]2 years ago

4 0

Answer:

133

Step-by-step explanation:

14 times 19 is 266 divided by 2 is 133

You might be interested in

The perimeter of the pentagon is 34 inches. Find the length of the side that is unknown. Explain your thinking.

Paladinen [302]

Answer: side = 6.8 inches

Step-by-step explanation:

Side of pentagon = perimeter/5

= 34/5 = 6.8

5 0

2 years ago

Of the cartons produced by a company, 8% have a puncture, 7% have a smashed corner, and 0.7% have both a puncture and a smashed

Viktor [21]

Answer:

The probability that a randomly selected carton has a puncture or a smashed corner is 0.143

Step-by-step explanation:

we know that P(A∪B) = P(A) + P(B) - P(A∩B).

since given that P(A) = Probability of getting puncture = 0.08

P(B) = probability of getting smashed corner = 0.07

P(A∩B) = probability of getting both puncture and smashed corner = 0.007

P(A∪B) = probability of getting any of them

so P(A∪B) = 0.08 + 0.07 -0.007 = O.143

5 0

2 years ago

Evaluate x(y-z)2 for =-1,y=5,and z=

Nata [24]

Answer:

The value of $x(y-z)^2$ is -16.

Step-by-step explanation:

We need to evaluate $x(y-z)^2$ for x = -1, y = 5 and let us assume that z = 1

It can be simply done by putting the values of x,y and z in the given expression.

$x(y-z)^2=(-1)(5-1)^2\\\\=-1(4)^2$

We know that the value of 4² = 16

So,

$x(y-z)^2=16\times -1\\\\=-16$

So, the value of $x(y-z)^2$ is -16.

6 0

3 years ago

Which describes the transformations of y = f(x) that would result in the graph of y = f(-x) – 7.

coldgirl [10]

Answer:

a reflection in the y-axis followed by a translation down by 7 units

Step-by-step explanation:

just answered it

3 0

2 years ago

Select the correct answer. Which expression is equivalent to 8x^2^3 sqrt 375x + 2^3 sqrt 3x^7, if x=0?

natima [27]

Answer:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

Step-by-step explanation:

The question is poorly formatted. The original question is:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

We have:

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7$

Open bracket

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^{3* \frac{2}{3}}) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(8^ \frac{2}{3} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 8 as 2^3

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^{3* \frac{2}{3}} *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =(2^2 *x^2) \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}$

Express 2^3 as 8

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{75x^3} + 8\sqrt{ 3x^7}$

Expand each exponent

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2 *3x} + 8\sqrt{ 3x * x^6}$

Split

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7}=4x^2 \sqrt{25x^2} *\sqrt{3x} + 8\sqrt{3x} * \sqrt{x^6}$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =4x^2 *5x *\sqrt{3x} + 8\sqrt{3x} * x^3$

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =20x^3\sqrt{3x} + 8x^3\sqrt{3x}$

Factorize

$(8x^3)^ \frac{2}{3} \sqrt{75x^3} + 2^3 \sqrt{ 3x^7} =28x^3\sqrt{3x}$

4 0

2 years ago

Read 2 more answers

Find the area of the triangle ​

Find the area of the triangle