8y^3+316
divide both sides by 4 (smallest divisable number) just say you tried to factor 2 and 3 and they weren't whole numbers and then you tried 4 and gave you the answer :)
4(2y^3+79)
Given:
The given function is:

To find:
The value of x that is in the domain.
Solution:
Domain is the set of input values.
We have,

We know that the square root is defined for non negative values. So,



Thus, the domain of the given function is all real number that are greater than or equal to 7.
In the given options 0, -3, 6 are less than 7 but 8 in option A is the only value that is greater than 7. So,
is in the domain of the given function.
Therefore, the correct option is A.
Answer:
C
Step-by-step explanation:
Inequalities of the type | x | > a, always have solutions of the form
x < - a or x > a, that is
Given
| 2x + 10 | > 26, then
2x + 10 < - 26 OR 2x + 10 > 26 ( subtract 10 from both sides of both )
2x < - 36 OR 2x > 16 ( divide both sides by 2 of both )
x < - 18 OR x > 8 → C
Answer:
b
Step-by-step explanation:
thbte