The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
<h3>Howe to solve for the rate of the plane and wind</h3>
In 7 hours the kilometer traveled = 4340
P + W = 4340/7
= 620
P-W = 3120/3 hours
= 1040
2p = 1040 + 620
= 1660
p =830
W = 1040 - 830
= 210
Hence the rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
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Answer:
Check the explanation
Step-by-step explanation:
Following table shows the calculations:
Delta, X Southwest , Y X^2 Y^2 XY
45.96 38.76 2112.3216 1502.3376 1781.4096
46.8 45.41 2190.24 2062.0681 2125.188
47.93 15.7 2297.2849 246.49 752.501
51.78 49.58 2681.1684 2458.1764 2567.2524
52.17 44.34 2721.7089 1966.0356 2313.2178
47.36 18 2242.9696 324 852.48
Total 292 211.79 14245.6934 8559.1077 10392.0488
Sample size: n =6
Now



The coefficient of correlation is :

For this case we have the following equation of motion:
h (t) = -16t ^ 2 + 90t
Equaling the equation to zero we have:
-16t ^ 2 + 90t = 0
We look for the roots of the polynomial:
(t) (- 16t + 90) = 0
t1 = 0 (initial position)
t2 = 90/16 = 5.625 s (time it reaches the ground again)
Answer:
it will return to the ground in:
t = 5.625 s
Obliviously 1/2.
If you roll a die and you get two times 3 the probability to get another 3 is always 1/6