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liubo4ka [24]
3 years ago
7

Mrs. Byrne's class went raspberry picking. The data show the weights of the cartoons of raspberries the students picked. Make a

tally table and a line plot to show the data. 3/4, 1/4, 2/4, 4/4, 1/4, 1/4, 2/4, 3/4, 3/4

Mathematics
1 answer:
Licemer1 [7]3 years ago
4 0
Here is what you tally chart/table would look like:

Weight     Tallies

1/4            lll
2/4            ll
3/4            lll
4/4            l


Here is what your line plot would look like:

X                     X
X          X         X 
<u>X          X         X         X
</u><u />1/4       2/4      3/4      4/4

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Tina collects stuffed animals. She has 8 teddy bears, 9 dogs, 10 frogs, and 6 monkeys. What is the ratio of monkeys to teddy
astraxan [27]

Answer:

it's c

Step-by-step explanation:

there are 8 bears and 6 monkeys!

hope this helps:)

3 0
3 years ago
X2 – 11x + 5 = -2x<br> Solve equation to the nearest tenth
Nataly [62]

Answer:

x = 5/7 -> 0.714285 which to the nearest tenth would be 0.7

Step-by-step explanation:

is it x*2 or x^2?

If it were x to the power of two, then the answer would be about x1 = 0.594875 and x2 = 8.40512

7 0
3 years ago
Evaluate the surface integral:S
rjkz [21]
Assuming S does not include the plane z=0, we can parameterize the region in spherical coordinates using

\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle

where 0\le u\le2\pi and 0\le v\le\dfrac\pi/2. We then have

x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v
(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v

Then the surface integral is equivalent to

\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du

We have

\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle
\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle
\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle
\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v

So the surface integral is equivalent to

\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du
=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv
=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw

where w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv.

=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}
=\dfrac{243}2\pi
4 0
3 years ago
A hallway measuring 90 feet x 7 feet requires 1/2 a fluid ounce of cleaning solution per square foot. How much cleaning solution
Vilka [71]
315 fluid ounces of solution
7 0
3 years ago
Determine whether quadrilateral ABCD is a rhombus, a rectangle, a square, a parallelogram, or none. List all that apply. Explain
svlad2 [7]

Answer:

  • ABCD is a rhombus, and a parallelogram

==================================

<h3>Given </h3>

  • Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)

First, plot the points (see attached picture).

Then, connect all the points.

<h3>We see that:</h3>

  • Opposite sides are parallel,
  • Diagonals are perpendicular.

From our observation the figure is rhombus.

Let's confirm it with the following.

1) Find midpoints of diagonals and compare.

  • AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
  • BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2

The midpoint of both diagonals is same (- 2, 2).

2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.

  • m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
  • m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3

  • m(AC) × m(BD) = 3/4 * (- 4/3) = - 1

<u>Confirmed.</u>

So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.

5 0
1 year ago
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