Answer:
Parameter
Explanation:
A parameter is a variable/argument of a function that are placed between the parentheses in the function's definition.
Hope this is clear :)
The answer is
Recipient's ability to open file
Size of file
Sometimes, it might occur that the email message attachment you’ve sent to someone has an error or is corrupt and thus, limits the recipient ability to open the file. Another factor is the size of the file. All email servers limit the size of the file attached in an email that a recipient can receive mainly because of security reasons. Google Mail, for instance, only allows you to send 25MB only. This might limit the ability to attach files to e-mail messages as well.
Answer:
Education
Explanation:
Most apps for <u>learning</u> a new language are for educational purposes and are most likely an education type of app.
Answer:see explanation
Explanation:
Hello, from your question I see that you need a program which based on countNum's value prints ready then all the numbers to 1 and finally go!, I'd appreciate if you provided information about the numbers after the example you gave as I do not know if they are to be printed too.
The solution I provide includes the countdown to 1 printing newline after each number and text. Try it out!
#include <stdio.h>
int main(void)
{
int countNum;
int i;
countNum = 22;
for ( i = countNum; i > 0; i--) {
if (i == countNum){
printf("Ready!\n");
}
printf("%d\n",i);
}
printf("Go!\n");
return 0;
}
Answer:
Answered below
Explanation:
//Program is written using Java programming language.
Class Person {
private string firstName;
private string lastName;
void set firstName(string a){
firstName = a;
}
string getFirstName(){
return firstName;
}
void setLastname( string b){
lastName = b;
}
string getLastName( ){
return lastName;
}
void displayDetails( ) {
System.out.print(firstName);
System.out.print (lastName);
}
}
//Test program
Class Main{
public static void main(String args [] ){
Person person = new Person( )
person.setFirstName("Karen")
System.out.print(person.getFirstName)
person.displayDetails()
}
}
