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zvonat [6]
2 years ago
14

Consider the following method, which is intended to return the index of the first negative integer in a given array of integers.

public int positionOfFirstNegative(int[] values) { int index = 0; while (values[index] >= 0) { index++; } return index; } What precondition is needed on the values array so that the method will work as intended?
Computers and Technology
1 answer:
Aleksandr [31]2 years ago
3 0

Answer:

The answer is "The array values must contain at least one negative integer".

Explanation:

In the above-given code, a method "positionOfFirstNegative" is declared, that accepts an array "values" as a parameter, inside the method an integer variable index is declared, that use in the while loop to check array value is greater than equal to 0, if the conditional is true it will increments the index value and return its value, that's why in this question array value include at least one negative value.

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The LList class is (mostly) the same one discussed in lecture, but you must write a sort() function that uses one of the three i
Vladimir79 [104]

Answer:

see explaination

Explanation:

#include <iostream>

#include <string>

using namespace std;

class LinkedList{

class Node{

public :

int data;

Node* next;

Node(int data){

this->data = data;

next = NULL;

}

};

public :

Node *head;

LinkedList(){

this->head = NULL;

}

void insert(int d){

Node* new_node = new Node(d);

new_node->next = head;

head = new_node;

}

// sort the list with selection sort algorithm.

// Pick the smallest element in the unsorted array and place in the first element in the unsorted.

void sort_list(){

if (head == NULL){

return;

}

Node* current = head;

while (current->next != NULL){

Node* min_node = current;

Node* traverse = current->next;

while(traverse != NULL){

if(traverse->data < min_node->data){

min_node = traverse;

}

traverse = traverse->next;

}

int temp = current->data;

current->data = min_node->data;

min_node->data = temp;

current = current->next;

}

}

void print_list(){

Node* current = head;

while(current !=NULL){

cout<<current->data<<" ";

current = current->next;

}

cout<<"\n";

}

};

int main(){

LinkedList ll;

for(int i=0;i<10;i++){

ll.insert(i);

}

ll.print_list();

cout<<"*******************************************\n";

ll.sort_list();

ll.print_list();

cout<<"*******************************************\n";

}

8 0
3 years ago
Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0
3 years ago
Pseudo code for rolling a dice
iogann1982 [59]

Answer:

Explanation:

In this exercise, you will roll a pair of dice until the numbers add up to a given number. You can assume that the given number is 2, 3, 6, or 12. Using pseudocode, write an algorithm that returns the number of times the dice is rolled to achieve this number.

3 0
2 years ago
Which of the following is the core communications protocol for the internet? telnet ftp tcp/ip ssl
inna [77]
Tcp/ip is the core communication protocol for the internet
4 0
3 years ago
To insert a footnote in a document, a user would navigate to the _____ tab.
Pachacha [2.7K]

Answer

References tab.

Explanation

In MS word documents, you can add footnotes and endnotes by;

• Clicking the area to add a footnote

• Clicking references, then insert Footnote. The word program will insert a reference mark in the text and will add the footnote mark at the bottom of the page

• Type a footnote text.

Hope this Helps!

3 0
3 years ago
Read 2 more answers
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