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4 years ago

1/6=?/18 this is for college basic math fractions

Mathematics

2 answers:

Anit [1.1K]4 years ago

6 0

3/18 because what you do to the denominator, you do to the numerator. Since 6x3 is 18, 1x3 is 3.

Darya [45]4 years ago

4 0

3/18 is your answer. the first thing is to look at the denominators to see how many 6's are in 18 since the first fraction has 1 in the numerator. 6 times 3 is 18 so you would also take 3 x the numerator of 1. Giving you 3/18 as your answer

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maxonik [38]

Answer with Step-by-step explanation:

We are given that

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$r'(t)=$

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$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

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pav-90 [236]

Answer:

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Step-by-step explanation:

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3 years ago

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notka56 [123]

1) Plug in 2 into the equation:
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4 years ago

For the diagram below, if < 4 = 4x - 2, and < 6 = 2x + 14, what is the value of x?

RUDIKE [14]

Applying the alternate interior angles theorem, the value of x is: D. 8.

<h3>What is the Alternate Interior Angles Theorem?</h3>

The alternate interior angles theorem states that interior angles that are alternate to each other along a transversal have equal measurement.

∠4 and ∠6 are alternate interior angles, therefore:

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Substitute

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x = 8 (option D).

Learn more about the alternate interior angles theorem on:

brainly.com/question/24839702

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