2y - x = 5
x^2 + y^2 - 25 = 0
x = 2y - 5
(2y-5)^2 + y^2 - 25 = 0
(2y-5)(2y-5) + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
y = 0 , y = 4
x = 2y - 5 , when y = 0
x = - 5
x = 2y - 5 , when y = 4
x = 8 - 5
x = 3
Answer:
<em>V = 1,568</em>
Step-by-step explanation:
<u>The Volume of a Square Pyramid</u>
Given a square-based pyramid of base side a and height h, the volume can be calculated with the formula:

We are given a square pyramid with a base side a=14 ft but we're missing the height. It can be calculated by using the right triangle shown in the image attached below, whose hypotenuse is 25 ft and one leg is 7 ft
We use Pythagora's theorem:

Solving for h:


The height is h=24 ft. Now the volume is calculated:

V = 1,568
Put it as number of donuts over price..... because it's x over y
4 is the x1 value, -8 is the y2 value, 8 is the x2 value, and 5 is the y2 value.
Answer:
32
Step-by-step explanation:
given the triangle is right triangle
c^2 = a^2 + b^2
40^2 = 24^2 + b^2
1600 = 576 + b^2
b^2 = 1024
b = 32