All categories

3 years ago

To which set of numbers does the number -12 belong?

1 answer:

3 0

That belongs to the integers set, also rational and real number set

integers are like -4,-3,-2,-1,0,1,2,3,4 etc
rational numbers are number that can be written in form a/b where a and b are integers and b≠0
real numbes include rational numbers

so integers, rational number and real numbers

You might be interested in

Explain how you find the sum of 46+7.

Savatey [412]

You add 7 more to 46 and the answer would be 53.

8 0

3 years ago

Read 2 more answers

Solve the equation 425x=850

mylen [45]

Answer:2

Step-by-step explanation:

DIVIDE 425 ON BOTH SIDES

AND U WILL GET 2

7 0

3 years ago

If f(x) = 3 – x2, find f(-2).

Rufina [12.5K]

Answer:

f(- 2) = - 1

Step-by-step explanation:

To evaluate f(- 2) substitute x = - 2 into f(x) , that is

f(- 2) = 3 - (- 2)² = 3 - 4 = - 1

4 0

3 years ago

Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

4 0

3 years ago

The cost of a set of 4 tire is $192. What is the unit rate for the cost of 1 tire?

hammer [34]

192 divided by 4 = 48

It costs $48 for one tire

4 0

4 years ago