Answer: 49.85%
Step-by-step explanation:
Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.
i.e.
and 
To find : The approximate percentage of lightbulb replacement requests numbering between 34 and 61.
i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and
.
i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between
and
. (1)
According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.
i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.
i.e.,The approximate percentage of lightbulb replacement requests numbering between
and
= 49.85%
⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%
The dog snored nine times. 1/3 of an hour is every 30 minute interval. 30 min + 30 min = 1 hour. Multiply this x3, and the answer is nine. A simpler way of thinking about this is 3 x 3 or 3 squared.
Answer:
y=2/7x
Step-by-step explanation:
y=mx+b where m=slope and b=y-intercept,
y=2/7x+0
y=2/7x
Answer:
Step-by-step explanation:
If you're allowed to use a calculator, type in 34, the division symbol, 6837, and finally enter:
34 / 6837 = 0.00497