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3 years ago

Help please, asap, And take your time answering please!

Mathematics

1 answer:

ankoles [38]3 years ago

5 0

Answer:

(a) 25

(b) (5+4)*2 +6 -2*2 -1

Step-by-step explanation:

(a) evaluating exponents:

6*7 -9*9 +64

Evaluating products:

42 -81 +64

Evaluating sums:

-39 +64

(b) The last three terms of the expression sum to +1, and it is fairly easy to modify the first two terms to make one term that has a value of 18. Then the expression evaluates as 18+1 = 19.

(5+4)*2 +6 -2*2 -1

(c) Evaluating parentheses:

= 9*2 +6 -2*2 -1

Evaluating products:

= 18 +6 -4 -1

Evaluating sums (left to right):

= 24 -4 -1

= 20 -1

= 19

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Answer:

a) 36°, b) 36°, c) 72°

Step-by-step explanation:

<h3>Given:</h3>

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a) ∠SQT is vertical with ∠PQR and therefore has equal measure

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3 years ago

What's the solution for 2x 7y=2 x y=-1

Lerok [7]

<span>Simplifying

(2x + -7y ) = 0

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(2x * (x + y) + -7y * (</span><span>x + y)) = 0
</span>((x * 2x + y * 2x) + -7y * (x + y)) = 0<span>

</span>Reorder the terms:
((2xy + 2x2) + -7y * (x + y)) = 0
((2xy + 2x2) + -7y * (x + y)) = 0
(2xy + 2x2 + (x * -7y + y * -7y)) = 0
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Reorder the terms:
(2xy + -7xy + 2x2 + -7y2) = 0
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<span>Combine like terms: 2xy + -7xy = -5xy
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</span>Solving -5xy + 2x2 + -7y2 = 0<span>

Solving for variable 'x'.

Factor a trinomial.
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3 years ago

What’s the answer for this question

devlian [24]

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3 years ago

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Aisha collects 1p coins and 2p coins. 24 of these are 1p coins. The probability of choosing a 2p coin at random is 1/2 How much

sdas [7]

Answer:

Aisha has 24 2p coins and 24 1p coins, then she has in total:

2p*(24) + 1*p*(24) = 48p + 24p = 72p

Step-by-step explanation:

Suppose that we have a set of N elements in a bag (if the bag is closed and we put our hand inside to grab one element, we could not distinguish them apart), and K of these elements have a given property (for example, these are red).

The probability of selecting at random one of these red elements is equal to the quotient between the number of elements with that property (K) and the total number of elements in the bag (N)

P = K/N

Now let's go to our problem.

We have 24 1p coins.

We have X 2p coins.

Then the total number of coins is: (24 + X)

We know that the probability of choosing at random a 2p coin is then:

P = X/(24 + X)

And we know that this is equal to 1/2

Then:

X/(24 + X) = 1/2

X = (1/2)*(24 + X) = 24/2 + X/2

X = 12 + X/2

X - X/2 = 12

X/2 = 12

X = 2*12 = 24

Then Aisha has 24 2p coins.

Aisha has 24 2p coins and 24 1p coins, then she has in total:

2p*(24) + 1*p*(24) = 48p + 24p = 72p

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