Let A be the event 'made by Apex and defective':
P(A) = 0.67 x 0.11 = 0.0737
Let B be the event 'made by B-ink and defective':
P(B) = 0.33 x 0.06 = 0.0198
Let C be the event 'made by Apex or B-ink and defective':
P(C) = P(A) + P(B) = 0.0737 + 0.0198 = 0.0935
P(defective and made by Apex) = 0.0737/0.0935 = 0.788
The answer is 0.788 or 78.8%.
You work it backwards.
-- If there were 4 children and each child got 4 pieces,
then the children got (4 x 4) = 16 pieces altogether.
-- That's what was left after he took 2 pieces for himself.
So he started with (16 + 2) = <em>18 pieces</em>.
Hi Jordyn! I think S is segment, B is base, and L is length. I hope this helped!
Answer:
∠2 and ∠5
Step-by-step explanation:
we know that
<u>Alternate Exterior Angles</u> are a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal
In this problem
∠12 and ∠2 are alternate exterior angles
∠12 and ∠5 are alternate exterior angles
therefore
∠2 and ∠5 are each separately alternate exterior angles with ∠12
False -11 is furter on the number line then -1
