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oee [108]
3 years ago
12

Expanded num for 373698

Mathematics
2 answers:
ivolga24 [154]3 years ago
4 0
300000+70000+3000+600+90+8
Feliz [49]3 years ago
4 0
300000+70000+3000+600+90+8
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Read 2 more answers
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000
valina [46]

Answer: 61,750 miles

Step-by-step explanation:

Given : The p-value of the tires to outlast the warranty = 0.96

The probability that corresponds to 0.96 from a Normal distribution table is 1.75.

Mean : \mu=60,000\text{ miles}

Standard deviation : \sigma=1000\text{ miles}

The formula for z-score is given by  : -

z=\dfrac{x-\mu}{\sigma}\\\\\Rightarrow\ 1.75=\dfrac{x-60000}{1000}\\\\\Rightarrow\ x-60000=1750\\\\\Rightarrow\ x=61750

Hence, the tread life of tire should be 61,750 miles if they want 96% of the tires to outlast the warranty.

3 0
3 years ago
PLZ HELP ME I WILL BRAINLIST YOU
AURORKA [14]

Answer:

B.   15 units^{2}

Step-by-step explanation:

4 0
3 years ago
30 + (.0825 x 30) + (15% x 30) =
Vanyuwa [196]

30×·15=4.50

then subtract 30 by 4.50 to get 25.50

.0825×30=2.475

now add 2.475+25.50+30= 57.975 round to 57.98


5 0
3 years ago
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