When stimulated by the binding of specific chemicals, the membranes of taste bud receptors and olfactory neurons?

2 answers:

8 0

Taste bud receptors if not stimulated are normally polarized. With the presence of the food, chemicals from the food bind with the cell protein which depolarized the cell membrane receptor. Depolarization will lead into the propagation of electric impulse. This will lead into the creation of sensory impulse. The larger number of the chemicals in the food will lead into a stronger impulse.

jasenka [17]4 years ago

7 0

The answer is depolarization. Depolarization is the influx of cations, especially sodium ions, from the extracellular fluid into the neuron cell hence generation an electrical impulse along a neuron. The resting potential of neurons is -70mV. When depolarized, the electronegativity in the inside of the neuron cell reduces.

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Read 2 more answers

If two orange heliodors have a child, what is the probability their child would be red?

Stels [109]

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25% or 1/4

Explanation:

The gene for colour in Heliodors is controlled by two contrasting alleles that codes for Red (R) and Yellow (Y) colours. However, these two alleles exhibit incomplete dominance, which is a phenomenon whereby a combination of both alleles gives rise to a third intermediate phenotype that is a blending of the other two parental phenotypes. In this case, both colours gives rise to a heterozygous Orange coloration (RY) in Heliodors.

However, if two orange Heliodors (RY) are crossed, four possible offsprings will be produced with the genotypes: RR, RY, RY, YY. This shows a phenotypic ratio of 1 red: 2orange: 1yellow. Hence, the probability of having a child with red coloration is 1 out of 4 possible offsprings i.e. 1/4.

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