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MAVERICK [17]
3 years ago
10

Re-write the equation 3x - y = 4 in slope-intercept form.

Mathematics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

a

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c

Rearrange 3x - y = 4 into this form ( add y to both sides )

3x = y + 4 ( subtract 4 from both sides )

3x - 4 = y OR y = 3x - 4 → a

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masha68 [24]
Are you looking for c? if so c=5
6 0
3 years ago
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Solve for these letters<br> X<br> Y<br> Z
tester [92]
Z = 140
X = 40
Y = 40
Explanation:
Z and the angle given (140 degrees) are vertical angles, and are therefore congruent
We know that x and y are vertical angles, so they are also congruent to each other
You know that together, the angles have to add up to 360
140 + 140 + x + y = 360
Another way of putting it:
360-280 = 80
Now, we have to divide by two since we need to find x AND y
80/2 = 40
Therefore, your answers for x and y are 40
To double check, you can add up the angles and see if they equal 360
140 + 140 + 40 + 40
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7 0
3 years ago
What is the volume?<br> 2 mm<br> 6 mm<br> 1 mm<br> cubic millimeters
worty [1.4K]
Assuming the 2,6,1 are length, width and height we can use the formula Volume= length • width • height. When you plug those in you will get 2•6•1= 12. The volume is 12 cubic millimeters. Or 12 cubed
4 0
1 year ago
A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square
kondaur [170]
This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

V = xxy = x^{2}y

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = x^{2}

Surface area of the rectangular sides = 4xy

Therefore, the total area of the cube is:

A = 48 ft^{2} =  x^{2} + 4xy

Isolating the variable y in terms of x:

y =  \frac{48- x^{2} }{4x}

Substituting this value in V:

V =  x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

\frac{dv}{dx} = 48-3x^{2} =0

Solving for x:

x =  \sqrt{\frac{48}{3}} =  \sqrt{16} = 4

Solving for y:

y =  \frac{48- 4^{2} }{(4)(4)} = 2

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width =  4 ft
Height = 2 ft

And its volume is:

V = (4^{2} )(2) = 32 ft^{3}

8 0
3 years ago
PLEASE HELP. ILL PICK BRAINIEST ANSWER
klasskru [66]

The graph shows the height of a kicked soccer ball f(x), in feet, depending on the distance from the kicker x, in feet

Part A: What do the x-intercepts of the graph represent?

The x intercept means value of x when h(x)=0. That is, the x-intercept signify the distance from kicker when height h(x) =0. The x intercept is (0,0) and (16,0).

So, when the kicker is at a distance of 0 feet or 16 feet, height h(x)=0 feet.

What does maximum value of the graph represent?

The maximum value of the graph signify maximum height the soccer ball can achieve. The maximum height the graph has is at (8,10). That is, when kicker is at a distance of 8 feet from the ball, the ball attains a maximum height of 10 feet.

What are the intervals where the function is increasing and decreasing, and what do they represent about distance and height?

The increasing interval is (-∞,8]. That is, the height of the ball increases when kicker is increasing as the distance increases from -∞ to 8. But, the height keeps on decreasing from 8 to ∞. As, x, distance increases from 8, the height decreases, Hence, decreasing interval [8,∞)

Part B: What is an approximate average rate of change of the graph from x=8 to x=13, and what does this rate represent?

average rate of change=\frac{f(x2)-f(x1)}{x2-x1}

where x2=13 and x1=8. That is, the interval in which we are looking for average rate of change

f(x2)=f(13)=5

f(x1)=f(8)=10

average rate of change =\frac{5-10}{13-8}

=\frac{-5}{5}

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average rate of change =-1.

This rate signify that height decreases by 1 feet as distance of the skipper increases by 1 feet (when distance, x is between 8 and 13)

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