Answer: h(x)
Explanation:
1) f(x) is not a function because there is an ambiguity for x = 4.
x = 4 belongs to both intervals - 2 ≤ x ≤ 4 and x ≥ 4
Then you find two different possible images for x: 0 and -(2)^2 = - 4.
That makes that f(x) be not a function.
2) similar thing happens with g(x)
as per the given relation the value of g(x) for x = 2 is 4 and 4+1 = 5. Which makes that g(x) be not a function.
3) j(x) is not a function because the image of x = -4 is -3(-4) = 12 and 3.
4) h(x) is a function, because there is not any ambiguity in its definition, for every x in its domain there is only one image h(x).
Is that the whole equation? Exactly from the book or paper?
This is a combination question
Hope this helps
Answer:
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Step-by-step explanation:


Hope this helped! :)
Answer:
Step-by-step explanation:
x² - x -6 = x² + 2x - 3x - 3*2
=x(x + 2) - 3(x + 2)
= (x + 2 )(x - 3)

