4 years ago

I need to find the zeros of the function:f(x)=2x^2-5x-3

Mathematics

1 answer:

GaryK [48]4 years ago

4 0

$2x^2-5x-3=0\\
2x^2-2x-3x-3=0\\
2x(x+1)-3(x+1)=0\\
(2x-3)(x+1)=0\\
x=\frac{3}{2} \vee x=-1$

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IRISSAK [1]

Answer:

Step-by-step explanation:

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6 0

3 years ago

Write an equation of the line that is perpendicular to 3x + 9y = 7 and passes through the point (6, 4).

musickatia [10]

Hi there!

The equation of any line perpendicular to
$ax + by = c$
is
$bx - ay = c$

Therefore, in this situation, the formula of the line would be
$9x - 3y = c$

Given that the line passes through the point (6, 4) we get
$9 \times 6 - 3 \times 4 = c$
$54 - 12 = c$
$c = 44$

Therefore, the equation of the line that is perpendicular to 3x + 9y = 7 and passes through (6, 4) is
$9x - 3y = 44$