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AlekseyPX
4 years ago
11

I need to find the zeros of the function:f(x)=2x^2-5x-3

Mathematics
1 answer:
GaryK [48]4 years ago
4 0
2x^2-5x-3=0\\
2x^2-2x-3x-3=0\\
2x(x+1)-3(x+1)=0\\
(2x-3)(x+1)=0\\
x=\frac{3}{2} \vee x=-1
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