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3 years ago

Find the domain of the following function f(x)=sqrt x-4. write your answer in interval notation.

Mathematics

2 answers:

AlladinOne [14]3 years ago

8 0

X has to be equal or greater than four, so the interval notation would be [4,∞)

zvonat [6]3 years ago

3 0

Answer:

$[4,\infty)$

Step-by-step explanation:

We have been given a function $f(x)=\sqrt{x-4}$ . We are asked to find the domain of our given function.

We know that domain of a function is all values of independent variable for which function is defined.

We also know that square root of negative numbers is not defined.

The domain of our given function will be all non-negative values of x as:

$x-4\geq 0$

$x-4+4\geq 0+4$

$x\geq 4$

Therefore, the domain of our given function is all values of x greater than or equal to 4 that is $[4,\infty)$ in interval notation.

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If f(x)= x^1/2 - x and g(x)= 2x^3 - x^1/2 - x, find f(x) - g(x)

Pavlova-9 [17]

Answer:

$-2x^3+2x^{1/2}$

Step-by-step explanation:

First, you have to substitute both functions into the equation to get:

$f(x)-g(x) = (x^{1/2}-x) - (2x^3-x^{1/2}-x)$

Then, you distribute the negative sign in front of g(x) to get:

$= x^{1/2} - x -2x^3+x^{1/2}+x$

And finally, you add/subtract the x's that have the same power to get:

$=-2x^3+2x^{1/2}$

3 0

3 years ago

From the graph; calculate: E=

Ket [755]

<h3>Answer:</h3>

c) 7π cm

<h3>Step-by-step explanation:</h3>

The length of an arc (s) is related to its central angle (θ) and the radius of the circle (r) by ...

... s = rθ . . . . . . . . . θ in radians

Here, the central angle measures are given in "grads". There are 400 grads in a circle, so 200 grads in π radians. To convert grads to radians, we multiply the number of grads by π/(200g).

Then the lengths of the arcs are ...

... arc AB = (20 cm)·(50g·(π/(200g))) = 5π cm

... arc BC = (10 cm)·(40g·(π/(200g))) = 2π cm

E = arc AB + arc BC = 5π cm + 2π cm = 7π cm

5 0

4 years ago

Which is greater 63cm or 6m

vesna_86 [32]

The answer should be 6 meters.

8 0

3 years ago

If r = 4 and ^a8 = 100, what is the first term of the geometric<br> sequence?

telo118 [61]

The first term of the geometric sequence is 0.0061

<u>Step-by-step explanation:</u>

The general form of geometric sequence is a, ar, ar²,ar³,.......

where,

a is the first term of the sequence.
r is the common ratio. Here, the common ratio r = 4.
The 8th term of the sequence is 100. Hence n = 8.

<u>The formula to find the nth term of the geometric sequence is given by :</u>

⇒ $n_{th} term = ar^{n-1}$

⇒ $8_{th}term = a\times4^{8-1}$

⇒ $100 = a \times 4^{7}$

⇒ $100 = a \times 16384$

⇒ $a = \frac{100}{16384}$

⇒ a = 0.0061

Therefore, the first term of the geometric sequence is 0.0061

6 0

3 years ago

Describe in words where the square root of 50 minus 10 would be plotted on a number line.

Dafna1 [17]

The required value lies Between 6 and 7, but closer to 6. Option C is correct.

Given that,
The square root of 50 minus 10 would be plotted on a number line.

<h3>What is a number line?</h3>

A number line is defined as the number marked on the line calibrated into an equal number of units. For example -1, 0, 1, and so on.

According to the question,
= √[50-10]
= √40
= 6.32
Which is closer to 6.

Thus, the required value lies Between 6 and 7, but closer to 6. Option C is correct.

Learn more about number line here:

brainly.com/question/17683084

#SPJ1

3 0

1 year ago