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PolarNik [594]
3 years ago
7

Half of 6900 and 8100

Mathematics
2 answers:
klio [65]3 years ago
5 0

6900 + 8100 = 15000

15000 divided by 2 = 7500

So your answer is 7500

viva [34]3 years ago
3 0

11550 is the answer hopfully it helps Good Luck!

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Angle 1 and Angle 2 form a linear pair. If the measure of angle is 113°, find the measure of angle 2.​
LuckyWell [14K]

Answer:

<2 =67

Step-by-step explanation:

A linear pair adds to 180 degrees

<1 + <2 =180

113+ <2 = 180

<2 = 180-113

<2 =67

5 0
3 years ago
Helppp I just need it to be explained. #7
IceJOKER [234]
#7 is the easiest one.

a + bi = -9 + 4i

see the expression on either side matches up so..
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5 0
3 years ago
2. TANIA HAS A JOB OFFER. SHE IS OFFERED EITHER $50 PER DAY OR $30 PER DAY PLUS A COMMISSION
DerKrebs [107]
50=30+3x
(Subtract 30 from both sides)
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8 0
3 years ago
consider the sequence 11; 5; -1; -7;.... determine the sequence of the nth term of the sequence! PLSSSS HELP​
STALIN [3.7K]

Answer:

Tn = 17-6n

Step-by-step explanation:

d = 5-11 = -6

Tn = a + (n-1)d = 11 + (n-1)×-6

= 11 -6n +6 = 17-6n

4 0
3 years ago
A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test thi
bearhunter [10]

Answer:

The statistic for this case would be:

z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}

And replacing we got:

z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92

Step-by-step explanation:

For this case we have the following info:

n =700 represent the sample size

X= 305 represent the number of employees that earn more than 50000

\hat p=\frac{305}{700}= 0.436

We want to test the following hypothesis:

Nul hyp. p \leq 0.4

Alternative hyp : p>0.4

The statistic for this case would be:

z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}

And replacing we got:

z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92

And the p value would be given by:

p_v = P(z>1.922)= 0.0274

4 0
4 years ago
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