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pshichka [43]
3 years ago
7

If 2/5 cup of coconut shavings covers 1/4 of a cake, then how much coconut shavings are needed for one cake? A. 3/5 cup B. 5/8 c

up C. 1 3/5 cup D. 10 cups
Mathematics
1 answer:
DanielleElmas [232]3 years ago
6 0

The right answer is Option C.

Step-by-step explanation:

Given,

2/5 cup of coconut shavings covers 1/4 of a cake,

\frac{2}{5}\ coconut\ shavings=\frac{1}{4}\ of\ cake

For one whole cake, we will multiply both sides with 4;

4*\frac{2}{5}=\frac{1}{4}*4\\\frac{8}{5} = 1\ cake

Writing in simplified fraction form;

1\ cake = 1\frac{3}{5}\ cups

The right answer is Option C.

Keywords: fractions, multiplication

Learn more about fractions at:

  • brainly.com/question/3617539
  • brainly.com/question/3638399

#LearnwithBrainly

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1. Try It # 1 A company sells doughnuts. They incur a fixed cost of $25,000 for rent, insurance, and other expenses. It costs $0
Y_Kistochka [10]

Answer:

The y-intercept is 25000 . The intercept is the fixed cost of the doughnut selling company.

Step-by-step explanation:

In the question, it is given that the fixed cost is $25000 and the expense to produce each doughnut is $0.25.

It is required to find and identify the y intercept.

To do so, use the equation derived in previous part of the exercise to interpret the slope. Compare the equation with standard equation of the line.

Step 1 of 1

The total cost of the company is the sum of fixed cost and the expenses for the doughnut, C=0.25x+25000.

Compare the equation with general linear equation y=mx+c.

The y-intercept is 25000 .

The intercept is the fixed cost of the doughnut selling company.

5 0
2 years ago
Determine formula of the nth term 2, 6, 12 20 30,42​
nalin [4]

Check the forward differences of the sequence.

If \{a_n\} = \{2,6,12,20,30,42,\ldots\}, then let \{b_n\} be the sequence of first-order differences of \{a_n\}. That is, for n ≥ 1,

b_n = a_{n+1} - a_n

so that \{b_n\} = \{4, 6, 8, 10, 12, \ldots\}.

Let \{c_n\} be the sequence of differences of \{b_n\},

c_n = b_{n+1} - b_n

and we see that this is a constant sequence, \{c_n\} = \{2, 2, 2, 2, \ldots\}. In other words, \{b_n\} is an arithmetic sequence with common difference between terms of 2. That is,

2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2

and we can solve for b_n in terms of b_1=4:

b_{n+1} = b_n + 2

b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2

b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2

and so on down to

b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)

We solve for a_n in the same way.

2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)

Then

a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)

a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))

a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))

and so on down to

a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2

\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}

6 0
2 years ago
Question 1 (1 point)
bearhunter [10]
It’s is b why u covering your camera lol
4 0
3 years ago
If you can do this thank you :)
garik1379 [7]

Answer:

391

Step-by-step explanation:

because according to the questions that's it

7 0
2 years ago
Need help hurry please
shusha [124]
The slope is the number next to the variable and the y intercept is the number after the slope.

#1. Slope= -3
Y-intercept=-3

#2. Slope=5/2
Y-intercept=-4

#3. Slope=1/3
Y-intercept=3

#4. Slope=-2
Y-intercept=2

#5. Slope=-2/5
Y-intercept=-2

#6. Slope=-2/3
Y-intercept=-2
6 0
3 years ago
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