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2 years ago

Plesse help geomrety

Mathematics

1 answer:

marin [14]2 years ago

8 0

X + number = 114
Make sure x is 50
Then switch it and
X + number = 50
Make sure it’s 14

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A company has 31 salespeople. A board member at the company asks for a list of the top 4 salespeople, ranked in order of effecti

kvv77 [185]

Answer:

31465 ways

Step-by-step explanation:

Given data

Let us apply the combination formula

nCr = n! / r! * (n - r)!

n= 31

r= 4

substitute

= 31!/4!(31-4)!

= 31!/4!(27)!

= 31*30*29*28*27!/ 4!(27)!

= 31*30*29*28/4!

=31*30*29*28/4*3*2*1

=755160/24

=31465 ways

Hence there are 31465 possible ways to rank it

8 0

2 years ago

What is the area of the triangle? no links just the answer plz.

nikitadnepr [17]

Answer:

A = 25

Step-by-step explanation:

Base = |-2-(-7)| = |-2+7| = 5

equation of the line that includes the base

x = 6 (because it is parallel to y axis)

the height passes to the point (-4,-4) and must be perpendicular to the base

the equation of the line of the base hasn’t the slope expressed, so the line of the height has a slope equal to 0

so the equation of the line is y= -4

the point (6,-4) is where the two lines intercept and it is the point where the height hit the base

height = |-4-6| = 10

A = (base x height)/2 = (5x10)/2 = 25

3 0

3 years ago

3-^1 x (4 x 6) x 2-^3

xeze [42]

$\huge{ \boxed{ \mathbf{ \blue{Problem:-}}}}$

$\bold{ {3}^{ - 1 \ } (4 \times 6) \times {2}^{ - 3} }$

$\huge{ \boxed{ \bf{ \blue{Solution:-}}}}$

$\bold{ {3}^{ - 1}(4 \times 6) \times {2}^{ - 3} }$

$= \bold{ \frac{1}{3}^{1} (4 \times 6) \times { \frac{1}{2}^{3} } }$

$= \bold{ \frac{1}{3} \times 24 \times \frac{1}{8} }$

$\bold{= 1}$

<h3><u>〜</u><u>Hope</u><u> it's</u><u> helpful</u></h3>

4 0

3 years ago

Read 2 more answers

1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro

alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

$P(VISA \:| \:AE) = 15\%\\$

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

$P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}$

For the given problem it becomes

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}$

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\$

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

8 0

3 years ago

What's the number before 277000

FinnZ [79.3K]

The number is 276999

5 0

2 years ago