Help with 1-5

A glass jar has a height of 5 inches and a radius of 2. 5 inches. vanessa wants to fill the jar with beads that cost $0. 12 per

Shalnov [3]

Answer:
height(h)= 5in
radius(r) =2.5in
Volume(V)= pi ×r^2 ×h
V=(22/7)2.5^2×5=98.21in^3
$0.12=1 in^3
Amount to be paid= 0.12×98.21
=$11.79

Step-by-step explanation:
Firstly, find the volume of the jar. When the filled with the beads to the brim, it will assume the shape of the jar, hence their volume will be equal. We assume that the jar is a cylinder. After you find the volume, multiply the volume by the amount per cubic inches.

6 0

2 years ago

Which list of angle measures could be the angle measures of a triangle?

Dovator [93]

Hello there! So the answer would be D: 35 degrees, 60 degrees and 85 degrees. We know this because angles in a triangle sum to 180 degrees. By simply adding each angle up, we can confirm that 35 + 60 + 85 = 180. :)

8 0

2 years ago

Can someone help me with this,'<br><br><br> PLEASE?!?!

Citrus2011 [14]

I think that the number of times you drink all the water in your bottle is independent, because the number of liters you drink depends on how much there is.

Independent- the number of times you drink all the water in your bottle
Dependent- the number of liters you drink

8 0

3 years ago

Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

so

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

6 0

3 years ago

Given that P = (-4, 11) and Q = (-5, 8), find the component form and magnitude of vector QP

Svetach [21]

The given points are
P = (-4,11)
Q = (-5,8)

The x-component of vector QP is
-4 - (-5) = 1
The y-component of vector QP is
11 - 8 = 3

The vector QP is
(1,3) or
$\vec{QP} = \hat{i} + 3\hat{j}$

The magnitude of the vector is
√(1² + 3²) = √(10)

Answer:
$\vec{QP} = \hat{i}+3\hat{j} \,\, or \,\, (1,3)$
The magnitude is √(10).

8 0

3 years ago