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2 years ago

Help with 1-5

Mathematics

1 answer:

jekas [21]2 years ago

6 0

it would be da families with 1 child

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PLEASE HELP!!! THANK YOU

loris [4]

Answer:

D. shows a 90º counterclock wise rotation

5 0

3 years ago

Find the area. The figure is not drawn to scale

poizon [28]

Answer:

96 square inches.

Step-by-step explanation:

From given picture we see that

BC=8 in

AD=10 in

Given that

AD=AB

Then AB=10 in

Apply Pythagorean theorem in triangle ABC to find AC

$(hypotenuse)^2=(base)^2+(perpendicular)^2$

$(AB)^2=(BC)^2+(AC)^2$

$(10)^2=(8)^2+(AC)^2$

$100=64+(AC)^2$

$100-64=(AC)^2$

$36=(AC)^2$

take square root

$6=AC$

Then area of triangle ABC $=\frac{1}{2}\left(base\right)\left(altitude\right)$

$=\frac{1}{2}\left(8\right)\left(6\right)=24$

There are total 4 congruent triangles.

Then total area of the given figure = 4(24)=96 square inches.

7 0

2 years ago

Please any help is necessary

Ugo [173]

Answer:

Option D. 50 ft

Step-by-step explanation:

we know that

The area of the figure is equal to the area of three rectangles

$A=18x+(48-36)(32-11)+(18)(32)$

$A=18x+(12)(21)+(18)(32)\\A=18x+828$

Remember that the area is given

$A= 1,728\ ft^2$

$18x+828=1,728$

solve for x

$18x=1,728-828\\18x=900\\x=50\ ft$

3 0

2 years ago

√(25 - 10 √(3) + 3)<br> (not as a decimal)

nikitadnepr [17]

Answer:

$\huge\boxed{\sqrt{25-10\sqrt3+3}=5-\sqrt3}$

Step-by-step explanation:

$\sqrt{25-10\sqrt3+3}=(*)\\\\25=5^2\\3=(\sqrt3)^2\\10\sqrt3=(2)(5)(\sqrt3)\\\\(*)=\sqrt{5^2-(2)(5)(\sqrt3)+(\sqrt3)^2}\\\\\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\=\sqrt{(5-\sqrt3)^2}\\\\\text{use}\ \sqrt{a^2}=|a|\\\\=|5-\sqrt3|=5-\sqrt3\\\\^{\text{because}\ 5>\sqrt3\to5-\sqrt3>0}$

6 0

2 years ago

HELP QUICK THIS IS EASY IM JUST DUM

Elena L [17]

Answer:

0.0332

Step-by-step explanation:

Min put too many zeros in front of 33.2. 33.2 with 3 zeros in front is 0.0332

4 0

1 year ago

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