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4 years ago

Write the equation of the line passing through the two points. Show that this line is perpendicular to the given line.

Mathematics

1 answer:

il63 [147K]4 years ago

5 0

Write the equation of the line passing through the two points. Show that this line is perpendicular to the given line.

(4,1) and (6,-5) y=1/3x-7

(1,-6) and (3,-10) y=1/2x-5

Please help, we learned this today and I’m really confused. How do you do it?

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4 years ago

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Based on the estimated cost of college from step 1, determine how you are going to pay for college. You will need to do some res

Nezavi [6.7K]

This is a budgeting exercise. Based on the estimated cost of college which was set at $58,000, the following steps indicate how I intend to pay for college:

Scholarship - 70% = $40,600
Work Study - 17.2% = $10,000
Loan - 12.76% <u> = $7, 400</u>

<h3>What is budgeting?</h3>

Budgeting is simply the process of outlining the total expense requirements of an individual person or a corporate entity and how those expenses will be satisfied and efficiently allocated.

From the above, the total sum of $58,000 will be satisfied from three sources:

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Learn more about budgeting at;

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2 years ago

Solve: (-5/6) × (9/20) + (-5/6) × 7/25 = ?

jonny [76]

$\bf \underline{★ How \:to\: do -} \\$

Here, we are given with four fractions to multiply two of them and to add two of them. If we add them directly by taking the LCM and adding them is not a similar way. We can clearly observe that in those four fractions, we have two fractions as common i.e, we have two fractions as same. If we have two fractions or numbers as same, we can solve the sum by an other concept called as distributive property. In this property, we multiply the common fraction with the sum of other two fractions. This concept can also be done with fractions as well as integers. So, let's solve!!

$\:$

$\bf \underline{➤ Solution-} \\$

${\tt \leadsto \dfrac{(-5)}{6} \times \dfrac{9}{20} + \dfrac{(-5)}{6} + \dfrac{7}{25}}$

Group the non-common fractions in bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9}{20} + \dfrac{7}{25} \bigg)}$

First we should solve the numbers in bracket.

LCM of 20 and 25 is 100.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{9 \times 5}{20 \times 5} + \dfrac{7 \times 4}{25 \times 4} \bigg)}$

Multiply the numerators and denominators in the bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45}{100} + \dfrac{28}{100} \bigg)}$

Now, write both numerators in bracket with a common denominator.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{45 + 28}{100} \bigg)}$

Now, add the numerators in bracket.

${\tt \leadsto \dfrac{(-5)}{6} \times \bigg( \dfrac{73}{100} \bigg)}$

Write the numerator and denominator in lowest form by cancellation method.

${\tt \leadsto \dfrac{\cancel{(-5)} \times 73}{6 \times \cancel{100}} = \dfrac{(-1) \times 73}{6 \times 20}}$

Now, multiply the numerators and denominators.

${\tt \leadsto \dfrac{(-73)}{120}}$

$\:$

${\red{\underline{\boxed{\bf So, \: the \: answer \: obtained \: is \: \: \dfrac{(-73)}{120}}}}}$

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3 years ago

Please help me with solving worded quadratic equations

nikklg [1K]

Answer to question 2 is 4 and 8 because 4+8=12 and 4 squared is 16 and 8 squared is 64, 16+64=80, hope this helps.

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3 years ago

dharmesh has a square garden with a perimeter of 132 feet is the area of the garden greater than 1,000 square feet.

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The area is 1089 square feet, so the area of the garden is greater than <span>1,000 square feet.</span>

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3 years ago