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seraphim [82]
3 years ago
15

73210 the digit 3 stands

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
5 0
The digit stands for 3,000.
Minchanka [31]3 years ago
3 0
To digit 3 stands for 3000
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latisha wants to buy pumpkins and autumn squash for a fall display. she has a budget of $117 but wants to buy more than 10 veget
Alenkinab [10]

Answer: 15 squash, 5 pumpkins; 15 squash, 10 pumpkins; 20 squash, 5 pumpkins.


Step-by-step explanation:

Then graph the system of inequalities: 3.5x + 5.59y (less than or equal to) 117; x + y > 10.

The first inequality is saying the cost of x squash and y pumpkins should total no more than $117.

The second inequality states x squash and y pumpkins should add up to more than 10.

6 0
3 years ago
Read 2 more answers
2
disa [49]

Solving for x...

22+0.50x=37+0.35x

22+0.15x=37

0.15x=15

x=100

3 0
3 years ago
X + ky = 1
Marina CMI [18]
X + k y = 1
k x + y = 1  / * ( - k )
----------------
      x + k y = 1
- k² x - k y = - k
--------------------
x - k² x = 1 - k
x ( 1 - k² ) = 1 - k
x = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
y = 1 - k( 1 - k )/( 1 - k² )
y = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
a ) For  k = - 1 this system has no solution.
b ) For k ≠ - 1 and k ≠ 1, the system has unique solution:
( x , y ) = ( 1/ (1 + k) ,  1/( 1 + k ) ).
c ) For k = 1, there are infinitely many solutions.

3 0
3 years ago
A car manufacturer rolled out a new car priced at $10,000, but not many people bought it. In the context of supply and demand, h
iogann1982 [59]
It may lower down 
because they wanna get rid of it 
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3 years ago
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Use calculus to find the volume of the following solid S:
Troyanec [42]

S casts a "shadow" on the x-y plane given by the set

S' = \left\{(x,y) ~:~ -1 \le x \le 1 \text{ and } x^2 \le y \le 1\right\}

Each cross section is a square whose side length is determined by the vertical distance between y = 1 and y = x², which is |1 - x²|. But since -1 ≤ x ≤ 1, this distance simplifies to 1 - x².

The volume of an infinitesimally thin section is then (1 - x²)² ∆x (where ∆x represents its thickness), and so the volume of S is

\displaystyle \int_{-1}^1 (1-x^2)^2 \, dx = \int_{-1}^1 (1 - 2x^2 + x^4) \, dx

The integrand is even, so this integral is equal to twice the integral over [0, 1] :

\displaystyle \int_{-1}^1 (1-x^2)^2 \, dx = 2 \int_0^1 (1 - 2x^2 + x^4) \, dx = 2 \left(1 - \frac23 + \frac15\right) = \boxed{\frac{16}{15}}

4 0
2 years ago
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