Distance from P to the x-axis = 2x distance from P to the yz-plane
<span>Distance to the x-axis of a point P=(x,y,z) is (y^2+z^2)^1/2 </span>
<span>Distance to the yz-plane of a point P=(x,y,z) is x </span>
<span>So your equation is: </span>
<span>(y^2+z^2)^1/2 = 2x </span>
<span>=> y^2 + z^2 = 4x^2 </span>
<span>=> y^2 + z^2 - 4x^2 = 0
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<span>Here you go .. ordered as you wish ..
0.836
</span><span>0.683
</span><span>0.386
</span><span>0.3</span>
Answer:
20
Step-by-step explanation:
Let's start by rewriting the second equation in terms of "x":
Subtract y from both sides:
Now, substitute "5-y" for "x" in the first equation:
Note that:
Cancel out like terms:
Subtract 25 from both sides:
Divide both sides by -10
Now, substitute this value back into either of the equations to solve for x.
Add 15/2 to both sides:
Now, find the difference:
2(m-27n) this is the answer
