The perimeter:
40+35+16+16+125.7= 232.7 m
btw lowkey frustrating that they alternate between cm and m
90 + 49 = 139
180 - 139 = 41
x = 41
Alrighty
squaer base so length=width, nice
v=lwh
but in this case, l=w, so replace l with w
V=w²h
and volume is 32000
32000=w²h
the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW
alrighty
we gots
SA=W²+4HW and
32000=W²H
we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute
SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W
take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?
0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W
so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H
the box is 20cm height and the width and length are 40cm
Answer:
b. 58%
Step-by-step explanation:
Calculate the area of the entire rectangle using the formula A = lw.
The lowercase "L" is for length.
"w" is for width.
The lighter square is 10 units long by 5 inches wide.
A = lw
A = (10 in)(5 in) Multiply
A = 50 in²
Calculate the area for the shaded rectangle, 7 inches by 3 inches.
A = lw
A = (7 in)(3 in) Multiply
A = 21 in²
Calculate the area for the non-shaded region by subtracting the shaded area from the total area.
50 in² - 21 in² = 29 in²
The chance that a point in the large rectangle will NOT be in the shaded region is 29/50.
Convert this fraction to decimal form by using a calculator. Divide the top number by the bottom number.
29/50 = 0.58
0.58 is in decimal form. To convert it to a percentage, multiply the number by 100.
0.58 = 58%
Therefore the probability that a point chosen inside the large rectangle is not in the shaded region is 58%.
Step-by-step explanation:
AB=28 !... .......hope this helps..