From the stemplot, it can be taken that:
Both were very consistent home run hitters, due to the great amount of seasons with at least 20 home runs. Bonds had the biggest outlier, with a season of 73 home runs, while Aaron distribution was less spread.
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- From the stemplot, it can be taken that Bonds had the biggest outlier, which was the season with 73 home runs.
- His season with the lowest amount of home runs was also less than Aaron, as he had a 5 home run season while Aaron lowest amount was 10.
- They both had a lot of seasons with at least 20 home runs, so both very consistent.
Thus, we can take that:
Both were very consistent home run hitters, due to the great amount of seasons with at least 20 home runs. Bonds had the biggest outlier, with a season of 73 home runs, while Aaron distribution was less spread.
A similar problem is given at brainly.com/question/24341344
The answer is
h= -41.36
You first multiply -8.1(-0.4) and you get 3.24.
Then you subtract 3.24 - 44.6 to get h.
Answer:
∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG
Step-by-step explanation:
We have that the initial triangles are equal. Let us check which components remain within the final triangles as the same. The only such components are the angles B and C. We now know that we have to apply a triangle equality criterion.
The triangles BGH and CIH are equal since the have 2 common sides and the respective interior angles are equal. Then we have that BI=GC and also that the respective angles B and C are equal. THen also HIJ=HGJ since they fill to 180 degrees with angles that are equal.
Hence by angle-side-angle the triangles BJI and CJG are equal.
∠BIJ ≅ ∠CGJ and ∠BJI ≅ ∠CJG
Answer:
1. 7/10, 2. 25, 3. 1/4 4. 4. 3/5, 5. A
Step-by-step explanation:
1. Make a fraction with the total number of cards at the bottom (60) and all the cards that are not green (aka yellow and blue) on top (42). Then simplify the fraction 42/60 by dividing both terms by 6 to get 7/10
2. For this one, first find how many students out of the first 80 liked basketball by subtracting the 60 students who liked other sports from 80. This gives you 20. Now you know that 20/80 students like basketball. Now simplify the fraction to get 1/4. Then find 1/4 of 100, because we know that 1/4 of students like basketball. 1/4 of 100 is 25.
3. This problem is exactly the same as number 1, except instead of adding all the other colors and putting them as a fraction over the total, just put the number of pink shirts over the total number of shirts to get 3/12. Then simplify it to 1/4, and that's your answer.
4. This is also similar to problems 1 and 3. Just put the number of heads coin tosses over the total and simplify it.
5. This one is very similar to all the problems so far. I will let you do this one on your own. Remember: The number of cases (rolls or colors or sports or cards etc.) that you want to find the probability for goes on top, and the total number of those things goes on the bottom. The bigger the fraction, the greater probability there is.
Note: Please only ask one question at a time on here instead of 5 at once. Since these problems are so similar, chances are, you could have figured them out on your own with a little help on one of them. You are more likely to get a quick answer if the answerer doesn't have to do as much work.
